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Solve Percent Applications

Solve Percent Applications

By the end of this section, you will be able to: translate and solve basic percent equations, solve percent applications, find percent increase and percent decrease, solve simple interest applications, and solve applications with discount or mark-up.

Translate and Solve Basic Percent Equations

We will solve percent equations using the methods we used to solve equations with fractions or decimals. Without the tools of algebra, the best method available to solve percent problems was by setting them up as proportions. Now, as an algebra student, you can just translate English sentences into algebraic equations and then solve the equations.

We can use any letter you like as a variable, but it is a good idea to choose a letter that will remind us of what we are looking for. We must be sure to change the given percent to a decimal when we put it in the equation.

Example. Translate and solve: What number is 35%35\% of 9090?

What number is 35% of 90?Translate into algebra. Let n=the number.n=0.3590Remember "of" means multiply, "is" means equals.Multiply.n=31.5 \begin{array}{lrcl} & \text{What number is } 35\% \text{ of } 90? && \\[4pt] \text{Translate into algebra. Let } n = \text{the number.} & n &=& 0.35 \cdot 90 \\[4pt] \text{Remember "of" means multiply, "is" means equals.} & & & \\[4pt] \text{Multiply.} & n &=& 31.5 \end{array}

31.531.5 is 35%35\% of 9090.

Translate and solve: What number is 45% of 80?

Translate and solve: What number is 55% of 60?

We must be very careful when we translate the words in the next example. The unknown quantity will not be isolated at first, like it was above. We will again use direct translation to write the equation.

Example. Translate and solve: 6.5%6.5\% of what number is $1.17\text{\textdollar}1.17?

6.5% of what number is $1.17?Translate. Let n=the number.0.065n=1.17Multiply.0.065n=1.17Divide both sides by 0.065 and simplify.n=18 \begin{array}{lrcl} & 6.5\% \text{ of what number is } \text{\textdollar}1.17? && \\[4pt] \text{Translate. Let } n = \text{the number.} & 0.065 \cdot n &=& 1.17 \\[4pt] \text{Multiply.} & 0.065n &=& 1.17 \\[4pt] \text{Divide both sides by 0.065 and simplify.} & n &=& 18 \end{array}

6.5%6.5\% of $18 is $1.17.

Translate and solve: 7.5% of what number is $1.95?

Translate and solve: 8.5% of what number is $3.06?

In the next example, we are looking for the percent.

Example. Translate and solve: 144144 is what percent of 9696?

144 is what percent of 96?Translate into algebra. Let p=the percent.144=p96Multiply.144=96pDivide by 96 and simplify.1.5=pConvert to percent.150%=p \begin{array}{lrcl} & 144 \text{ is what percent of } 96? && \\[4pt] \text{Translate into algebra. Let } p = \text{the percent.} & 144 &=& p \cdot 96 \\[4pt] \text{Multiply.} & 144 &=& 96p \\[4pt] \text{Divide by 96 and simplify.} & 1.5 &=& p \\[4pt] \text{Convert to percent.} & 150\% &=& p \end{array}

144144 is 150%150\% of 9696. Note that we are asked to find percent, so we must have our final result in percent form.

Translate and solve: 110 is what percent of 88? Give the percent as a number (e.g. enter 40 for 40%).

Translate and solve: 126 is what percent of 72? Give the percent as a number (e.g. enter 40 for 40%).

Solve Applications of Percent

Many applications of percent — such as tips, sales tax, discounts, and interest — occur in our daily lives. To solve these applications we translate to a basic percent equation, just as we solved above. Once we translate the sentence into a percent equation, we know how to solve it.

We will restate the problem-solving strategy we used earlier for easy reference.

Use a Problem-Solving Strategy to Solve an Application.

  1. Read the problem. Make sure all the words and ideas are understood.
  2. Identify what we are looking for.
  3. Name what we are looking for. Choose a variable to represent that quantity.
  4. Translate into an equation. It may be helpful to restate the problem in one sentence with all the important information. Then translate the English sentence into an algebraic equation.
  5. Solve the equation using good algebra techniques.
  6. Check the answer in the problem and make sure it makes sense.
  7. Answer the question with a complete sentence.

Now that we have the strategy to refer to, and have practiced solving basic percent equations, we are ready to solve percent applications. Be sure to ask yourself if your final answer makes sense — since many of the applications will involve everyday situations, you can rely on your own experience.

Example. Dezohn and his girlfriend enjoyed a nice dinner at a restaurant and his bill was $68.50\text{\textdollar}68.50. He wants to leave an 18%18\% tip. If the tip will be 18%18\% of the total bill, how much tip should he leave?

Step
Identify what we are looking for.The amount of tip Dezohn should leave
Name what we are looking for.Let t=t = amount of tip.
Translate into an equation.The tip is 18%18\% of the total bill: t=0.1868.50t = 0.18 \cdot 68.50
Solve the equation.t=12.33t = 12.33
Check.Does this make sense? Yes — 20%20\% of $70 is $14, close to $12.33.
Answer the question with a complete sentence.Dezohn should leave a tip of $12.33\text{\textdollar}12.33.

Cierra and her sister enjoyed a dinner in a restaurant and the bill was $81.50. If she wants to leave 18% of the total bill as her tip, how much should she leave?

Kimngoc had lunch at her favorite restaurant. She wants to leave 15% of the total bill as her tip. If her bill was $14.40, how much will she leave for the tip?

Example. The label on Masao’s breakfast cereal said that one serving of cereal provides 8585 milligrams (mg) of potassium, which is 2%2\% of the recommended daily amount. What is the total recommended daily amount of potassium?

Step
Identify what we are looking for.The total amount of potassium that is recommended
Name what we are looking for.Let a=a = total amount of potassium.
Translate into an equation.8585 mg is 2%2\% of the total amount: 85=0.02a85 = 0.02 \cdot a
Solve the equation.4,250=a4{,}250 = a
Check.Does this make sense? Yes — 2%2\% is a small percent and 8585 is a small part of 4,2504{,}250.
Answer the question with a complete sentence.The recommended daily amount of potassium is 4,2504{,}250 mg.

One serving of wheat square cereal has seven grams of fiber, which is 28% of the recommended daily amount. What is the total recommended daily amount of fiber, in grams?

One serving of rice cereal has 190 mg of sodium, which is 8% of the recommended daily amount. What is the total recommended daily amount of sodium, in mg?

Example. Mitzi received some gourmet brownies as a gift. The wrapper said each brownie was 480480 calories, and had 240240 calories of fat. What percent of the total calories in each brownie comes from fat?

Step
Identify what we are looking for.The percent of the total calories from fat
Name what we are looking for.Let p=p = percent of fat.
Translate into an equation.What percent of 480480 is 240240: p480=240p \cdot 480 = 240
Solve the equation.480p=240480p = 240, so p=0.5=50%p = 0.5 = 50\%
Check.Does this make sense? Yes — 240240 is half of 480480, so 50%50\% makes sense.
Answer the question with a complete sentence.Of the total calories in each brownie, 50%50\% is fat.

Solve. Round to the nearest whole percent. Veronica is planning to make muffins from a mix. The package says each muffin will be 230 calories and 60 calories will be from fat. What percent of the total calories is from fat? Give the percent as a number (e.g. enter 40 for 40%).

Solve. The mix Ricardo plans to use to make brownies says that each brownie will be 190 calories, and 76 calories are from fat. What percent of the total calories are from fat? Give the percent as a number (e.g. enter 40 for 40%).

Find Percent Increase and Percent Decrease

People in the media often talk about how much an amount has increased or decreased over a certain period of time. They usually express this increase or decrease as a percent.

To find the percent increase, first we find the amount of increase, the difference of the new amount and the original amount. Then we find what percent the amount of increase is of the original amount.

Find the Percent Increase.

  1. Find the amount of increase: new amountoriginal amount=increase\text{new amount} - \text{original amount} = \text{increase}.
  2. Find the percent increase. The increase is what percent of the original amount?

Example. In 20112011, the California governor proposed raising community college fees from $26\text{\textdollar}26 a unit to $36\text{\textdollar}36 a unit. Find the percent increase. (Round to the nearest tenth of a percent.)

Step
Identify what we are looking for.The percent increase
Name what we are looking for.Let p=p = the percent.
First find the amount of increase.3626=1036 - 26 = 10
Find the percent: increase is what percent of the original amount?10=p2610 = p \cdot 26
Solve the equation.10=26p10 = 26p, so 0.385=p0.385 = p
Round to the nearest tenth.38.5%=p38.5\% = p
Check.Does this make sense? Yes — 38.5%38.5\% is close to 13\tfrac{1}{3}, and 1010 is close to 13\tfrac{1}{3} of 2626.
Answer the question with a complete sentence.The new fees represent a 38.5%38.5\% increase over the old fees.

Notice that we rounded the division to the nearest thousandth in order to round the percent to the nearest tenth.

Find the percent increase. Round to the nearest tenth of a percent. In 2011, the IRS increased the deductible mileage cost to 55.5 cents from 51 cents. Give the percent as a number (e.g. enter 40 for 40%).

Find the percent increase. In 1995, the standard bus fare in Chicago was $1.50. In 2008, the standard bus fare was $2.25. Give the percent as a number (e.g. enter 40 for 40%).

Finding the percent decrease is very similar to finding the percent increase, but now the amount of decrease is the difference of the original amount and the new amount. Then we find what percent the amount of decrease is of the original amount.

Find the Percent Decrease.

  1. Find the amount of decrease: original amountnew amount=decrease\text{original amount} - \text{new amount} = \text{decrease}.
  2. Find the percent decrease. The decrease is what percent of the original amount?

Example. The average price of a gallon of gas in one city in June 20142014 was $3.71\text{\textdollar}3.71. The average price in that city in July was $3.64\text{\textdollar}3.64. Find the percent decrease.

Step
Identify what we are looking for.The percent decrease
Name what we are looking for.Let p=p = the percent decrease.
First find the amount of decrease.3.713.64=0.073.71 - 3.64 = 0.07
Find the percent: decrease is what percent of the original amount?0.07=p3.710.07 = p \cdot 3.71
Solve the equation.0.07=3.71p0.07 = 3.71p, so 0.019=p0.019 = p
Round to the nearest tenth.1.9%=p1.9\% = p
Check.Does this make sense? Yes — if the original price was $4, a 2%2\% decrease would be 88 cents.
Answer the question with a complete sentence.The price of gas decreased 1.9%1.9\%.

Find the percent decrease. Round to the nearest tenth of a percent. The population of North Dakota was about 672,000 in 2010. The population is projected to be about 630,000 in 2020. Give the percent as a number (e.g. enter 40 for 40%).

Find the percent decrease. Last year, Sheila's salary was $42,000. Because of furlough days, this year, her salary was $37,800. Give the percent as a number (e.g. enter 40 for 40%).

Solve Simple Interest Applications

Do you know that banks pay you to keep your money? The money a customer puts in the bank is called the principal, PP, and the money the bank pays the customer is called the interest. The interest is computed as a certain percent of the principal; this is called the rate of interest, rr. We usually express rate of interest as a percent per year, and we calculate it by using the decimal equivalent of the percent. The variable tt (for time) represents the number of years the money is in the account.

To find the interest we use the simple interest formula, I=PrtI = Prt.

Simple Interest. If an amount of money, PP, called the principal, is invested for a period of tt years at an annual interest rate rr, the amount of interest, II, earned is

I=PrtI = Prt

where I=I = interest, P=P = principal, r=r = rate, and t=t = time. Interest earned according to this formula is called simple interest.

Interest may also be calculated another way, called compound interest. This type of interest will be covered in later math classes.

The formula we use to calculate simple interest is I=PrtI = Prt. To use the formula, we substitute in the values the problem gives us for the variables, and then solve for the unknown variable. It may be helpful to organize the information in a chart.

Example. Nathaly deposited $12,500\text{\textdollar}12{,}500 in her bank account where it will earn 4%4\% interest. How much interest will Nathaly earn in 55 years?

I=?P=$12,500r=4%t=5 yearsI = ? \qquad P = \text{\textdollar}12{,}500 \qquad r = 4\% \qquad t = 5 \text{ years}
Step
Identify what we are looking for.The amount of interest earned
Name what we are looking for.Let I=I = the amount of interest.
Translate into an equation. Write the formula, and substitute in the given information.I=PrtI = Prt, so I=(12,500)(0.04)(5)I = (12{,}500)(0.04)(5)
Solve the equation.I=2,500I = 2{,}500
Check.Does this make sense? Is $2,500\text{\textdollar}2{,}500 a reasonable interest on $12,500\text{\textdollar}12{,}500? Yes.
Answer the question with a complete sentence.The interest is $2,500\text{\textdollar}2{,}500.

Areli invested a principal of $950 in her bank account with interest rate 3%. How much interest did she earn in 5 years?

Susana invested a principal of $36,000 in her bank account with interest rate 6.5%. How much interest did she earn in 3 years?

There may be times when we know the amount of interest earned on a given principal over a certain length of time, but we don’t know the rate. To find the rate, we use the simple interest formula, substitute in the given values for the principal and time, and then solve for the rate.

Example. Loren loaned his brother $3,000\text{\textdollar}3{,}000 to help him buy a car. In 44 years his brother paid him back the $3,000\text{\textdollar}3{,}000 plus $660\text{\textdollar}660 in interest. What was the rate of interest?

I=$660P=$3,000r=?t=4 yearsI = \text{\textdollar}660 \qquad P = \text{\textdollar}3{,}000 \qquad r = ? \qquad t = 4 \text{ years}
Step
Identify what we are looking for.The rate of interest
Name what we are looking for.Let r=r = the rate of interest.
Translate into an equation. Write the formula, and substitute in the given information.I=PrtI = Prt, so 660=(3,000)r(4)660 = (3{,}000)r(4)
Solve the equation. Divide, and change to percent form.660=12,000r660 = 12{,}000r, so 0.055=r0.055 = r, so 5.5%=r5.5\% = r
Check.I=PrtI = Prt: 660=?(3,000)(0.055)(4)660 \stackrel{?}{=} (3{,}000)(0.055)(4), which simplifies to 660=660660 = 660. ✓
Answer the question with a complete sentence.The rate of interest was 5.5%5.5\%.

Notice that in this example, Loren’s brother paid Loren interest, just like a bank would have paid interest if Loren invested his money there.

Jim loaned his sister $5,000 to help her buy a house. In 3 years, she paid him the $5,000, plus $900 interest. What was the rate of interest? Give the percent as a number (e.g. enter 4 for 4%).

Hang borrowed $7,500 from her parents to pay her tuition. In 5 years, she paid them $1,500 interest in addition to the $7,500 she borrowed. What was the rate of interest? Give the percent as a number (e.g. enter 4 for 4%).

Example. Eduardo noticed that his new car loan papers stated that with a 7.5%7.5\% interest rate, he would pay $6,596.25\text{\textdollar}6{,}596.25 in interest over 55 years. How much did he borrow to pay for his car?

Step
Identify what we are looking for.The amount borrowed (the principal)
Name what we are looking for.Let P=P = principal borrowed.
Translate into an equation. Write the formula, and substitute in the given information.I=PrtI = Prt, so 6,596.25=P(0.075)(5)6{,}596.25 = P(0.075)(5)
Solve the equation.6,596.25=0.375P6{,}596.25 = 0.375P, so 17,590=P17{,}590 = P
Check.6,596.25=?(17,590)(0.075)(5)6{,}596.25 \stackrel{?}{=} (17{,}590)(0.075)(5), which simplifies to 6,596.25=6,596.256{,}596.25 = 6{,}596.25. ✓
Answer the question with a complete sentence.The principal was $17,590\text{\textdollar}17{,}590.

Sean's new car loan statement said he would pay $4,866.25 in interest from an interest rate of 8.5% over 5 years. How much did he borrow to buy his new car?

In 5 years, Gloria's bank account earned $2,400 interest at 5%. How much had she deposited in the account?

Solve Applications with Discount or Mark-up

Applications of discount are very common in retail settings. When you buy an item on sale, the original price has been discounted by some dollar amount. The discount rate, usually given as a percent, is used to determine the amount of the discount. To determine the amount of discount, we multiply the discount rate by the original price.

Discount.

amount of discount=discount rate×original price\text{amount of discount} = \text{discount rate} \times \text{original price}

sale price=original priceamount of discount\text{sale price} = \text{original price} - \text{amount of discount}

Keep in mind that the sale price should always be less than the original price.

Example. Elise bought a dress that was discounted 35%35\% off of the original price of $140\text{\textdollar}140. What was (a) the amount of discount and (b) the sale price of the dress?

(a)

Step
Identify what we are looking for.The amount of discount
Name what we are looking for.Let d=d = the amount of discount.
Translate into an equation.The discount is 35%35\% of $140\text{\textdollar}140: d=0.35(140)d = 0.35(140)
Solve the equation.d=49d = 49
Check.Is a $49\text{\textdollar}49 discount reasonable for a $140\text{\textdollar}140 dress? Yes.
Answer with a complete sentence.The amount of discount was $49\text{\textdollar}49.

(b) Read the problem again.

Step
Identify what we are looking for.The sale price of the dress
Name what we are looking for.Let s=s = the sale price.
Translate into an equation.The sale price is the $140\text{\textdollar}140 minus the $49\text{\textdollar}49 discount: s=14049s = 140 - 49
Solve the equation.s=91s = 91
Check.Is the sale price less than the original price? Yes — $91\text{\textdollar}91 is less than $140\text{\textdollar}140.
Answer with a complete sentence.The sale price of the dress was $91\text{\textdollar}91.

Sergio bought a belt that was discounted 40% from an original price of $29. Find the amount of discount.

Sergio bought a belt that was discounted 40% from an original price of $29. Find the sale price.

Oscar bought a barbecue that was discounted 65% from an original price of $395. Find the amount of discount.

There may be times when we know the original price and the sale price, and we want to know the discount rate. To find the discount rate, first we will find the amount of discount and then use it to compute the rate as a percent of the original price.

Example. Jeannette bought a swimsuit at a sale price of $13.95\text{\textdollar}13.95. The original price of the swimsuit was $31\text{\textdollar}31. Find (a) the amount of discount and (b) the discount rate.

(a)

Step
Identify what we are looking for.The amount of discount
Name what we are looking for.Let d=d = the amount of discount.
Translate into an equation.The discount is the difference between the original price and the sale price: d=3113.95d = 31 - 13.95
Solve the equation.d=17.05d = 17.05
Check.Is 17.0517.05 less than 3131? Yes.
Answer with a complete sentence.The amount of discount was $17.05\text{\textdollar}17.05.

(b) Read the problem again.

Step
Identify what we are looking for.The discount rate
Name what we are looking for.Let r=r = the discount rate.
Translate into an equation.The discount of $17.05\text{\textdollar}17.05 is what percent of $31\text{\textdollar}31: 17.05=r3117.05 = r \cdot 31
Solve the equation. Divide, and change to percent form.17.05=31r17.05 = 31r, so 0.55=r0.55 = r, so r=55%r = 55\%
Check.Is $17.05\text{\textdollar}17.05 equal to 55%55\% of $31\text{\textdollar}31? 17.05=?0.55(31)17.05 \stackrel{?}{=} 0.55(31), which simplifies to 17.05=17.0517.05 = 17.05. ✓
Answer with a complete sentence.The rate of discount was 55%55\%.

Lena bought a kitchen table at the sale price of $375.20. The original price of the table was $560. Find the amount of discount.

Lena bought a kitchen table at the sale price of $375.20. The original price of the table was $560. Find the discount rate. Give the percent as a number (e.g. enter 40 for 40%).

Nick bought a multi-room air conditioner at a sale price of $340. The original price of the air conditioner was $400. Find the amount of discount.

Applications of mark-up are very common in retail settings. The price a retailer pays for an item is called the original cost. The retailer then adds a mark-up to the original cost to get the list price, the price he sells the item for. The mark-up is usually calculated as a percent of the original cost. To determine the amount of mark-up, multiply the mark-up rate by the original cost.

Mark-Up.

amount of mark-up=mark-up rate×original cost\text{amount of mark-up} = \text{mark-up rate} \times \text{original cost}

list price=original cost+amount of mark-up\text{list price} = \text{original cost} + \text{amount of mark-up}

Keep in mind that the list price should always be more than the original cost.

Example. Adam’s art gallery bought a photograph at original cost $250\text{\textdollar}250. Adam marked the price up 40%40\%. Find (a) the amount of mark-up and (b) the list price of the photograph.

(a)

Step
Identify what we are looking for.The amount of mark-up
Name what we are looking for.Let m=m = the amount of markup.
Translate into an equation.The mark-up is 40%40\% of the $250\text{\textdollar}250 original cost: m=0.40250m = 0.40 \cdot 250
Solve the equation.m=100m = 100
Check.Is 100100 less than half of 250250? Yes, and 40%40\% is less than one-half.
Answer with a complete sentence.The mark-up on the photograph was $100\text{\textdollar}100.

(b) Read the problem again.

Step
Identify what we are looking for.The list price
Name what we are looking for.Let p=p = the list price.
Translate into an equation.The list price is the original cost plus the mark-up: p=250+100p = 250 + 100
Solve the equation.p=350p = 350
Check.Is the list price more than the original cost? Is $350\text{\textdollar}350 more than $250\text{\textdollar}250? Yes.
Answer with a complete sentence.The list price of the photograph was $350\text{\textdollar}350.

Jim's music store bought a guitar at original cost $1,200. Jim marked the price up 50%. Find the amount of mark-up.

Jim's music store bought a guitar at original cost $1,200. Jim marked the price up 50%. Find the list price.

The Auto Resale Store bought Pablo's Toyota for $8,500. They marked the price up 35%. Find the amount of mark-up.

Key terms

percent equation — an equation of the form “part == percent ×\times whole,” translated directly from an English sentence using “of” for multiplication and “is” for equals. percent increase — the amount of increase (new amount minus original amount), expressed as a percent of the original amount. percent decrease — the amount of decrease (original amount minus new amount), expressed as a percent of the original amount. principal — the amount of money deposited or borrowed. interest — money paid on a principal, computed as a percent of the principal. rate of interest — the percent used to compute interest, usually stated per year. simple interest — interest computed using the formula I=PrtI = Prt. discount rate — the percent of the original price that is subtracted to give the sale price. mark-up — the amount added to a retailer’s original cost, usually calculated as a percent of that cost, to get the list price.


This section is adapted from Elementary Algebra 2e, Section 3.2: Solve Percent Applications by Lynn Marecek, MaryAnne Anthony-Smith, and Andrea Honeycutt Mathis, © OpenStax, licensed under CC BY-NC-SA 4.0. Access the original for free at openstax.org. Changes: recreated the step-by-step solution tables as markdown tables; omitted the Be Prepared quiz, Self Check checklist, media links, and end-of-section exercises; and converted the practice problems (“Try Its”) into interactive exercises with instant feedback.