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Integer Exponents and Scientific Notation

Integer Exponents and Scientific Notation

By the end of this section, you will be able to: use the definition of a negative exponent; simplify expressions with integer exponents; convert from decimal notation to scientific notation; convert scientific notation to decimal form; and multiply and divide using scientific notation.

Use the Definition of a Negative Exponent

We saw earlier in this chapter that the Quotient Property for Exponents has two forms depending on whether the exponent is larger in the numerator or the denominator.

Quotient Property for Exponents. If aa is a real number, a0a \neq 0, and mm and nn are whole numbers, then

aman=amn, m>nandaman=1anm, n>m\frac{a^m}{a^n} = a^{m-n},\ m > n \qquad \text{and} \qquad \frac{a^m}{a^n} = \frac{1}{a^{n-m}},\ n > m

What if we just subtract exponents regardless of which is larger? Let’s consider x2x5\tfrac{x^2}{x^5}. We subtract the exponent in the denominator from the exponent in the numerator:

x2x5=x25=x3\frac{x^2}{x^5} = x^{2-5} = x^{-3}

We can also simplify x2x5\tfrac{x^2}{x^5} by dividing out common factors:

x2x5=xxxxxxx=1x3\frac{x^2}{x^5} = \frac{x \cdot x}{x \cdot x \cdot x \cdot x \cdot x} = \frac{1}{x^3}

This implies that x3=1x3x^{-3} = \tfrac{1}{x^3}, and it leads us to the definition of a negative exponent.

Negative Exponent. If nn is an integer and a0a \neq 0, then

an=1ana^{-n} = \frac{1}{a^n}

The negative exponent tells us we can rewrite the expression by taking the reciprocal of the base and then changing the sign of the exponent.

Any expression that has negative exponents is not considered to be in simplest form. We will use the definition of a negative exponent and other properties of exponents to write an expression with only positive exponents. For example, if after simplifying an expression we end up with the expression x3x^{-3}, we will take one more step and write 1x3\tfrac{1}{x^3}. The answer is considered to be in simplest form when it has only positive exponents.

Example. Simplify: (a) 424^{-2} (b) 10310^{-3}.

(a) Use the definition of a negative exponent, an=1ana^{-n} = \tfrac{1}{a^n}: 42=142=1164^{-2} = \tfrac{1}{4^2} = \tfrac{1}{16}.

(b) Use the definition of a negative exponent: 103=1103=1100010^{-3} = \tfrac{1}{10^3} = \tfrac{1}{1000}.

Simplify: 232^{-3}.

Simplify: 323^{-2}.

When we raised a fraction whose numerator is one and whose denominator is an integer to a negative exponent, we found:

1an=11an=1an1=an\frac{1}{a^{-n}} = \frac{1}{\tfrac{1}{a^n}} = 1 \cdot \frac{a^n}{1} = a^n

This leads to the Property of Negative Exponents.

Property of Negative Exponents. If nn is an integer and a0a \neq 0, then

1an=an\frac{1}{a^{-n}} = a^n

Example. Simplify: (a) 1y4\tfrac{1}{y^{-4}} (b) 132\tfrac{1}{3^{-2}}.

(a) Use the Property of Negative Exponents, 1an=an\tfrac{1}{a^{-n}} = a^n: 1y4=y4\tfrac{1}{y^{-4}} = y^4.

(b) Use the Property of Negative Exponents, then simplify: 132=32=9\tfrac{1}{3^{-2}} = 3^2 = 9.

Simplify: 1p8\tfrac{1}{p^{-8}}. Write the answer as a power of p.

Simplify: 143\tfrac{1}{4^{-3}}.

Suppose now we have a fraction raised to a negative exponent. Using the definition of a negative exponent, we can show that taking the reciprocal of the base and changing the sign of the exponent works here too. For example, (34)2=(43)2\left(\tfrac{3}{4}\right)^{-2} = \left(\tfrac{4}{3}\right)^2. This leads us to the Quotient to a Negative Exponent Property.

Quotient to a Negative Exponent Property. If aa and bb are real numbers, a0a \neq 0, b0b \neq 0, and nn is an integer, then

(ab)n=(ba)n\left(\frac{a}{b}\right)^{-n} = \left(\frac{b}{a}\right)^n

Example. Simplify: (a) (57)2\left(\tfrac{5}{7}\right)^{-2} (b) (2xy)3\left(-\tfrac{2x}{y}\right)^{-3}.

(a) Use the Quotient to a Negative Exponent Property — take the reciprocal of the fraction and change the sign of the exponent, then simplify:

(57)2=(75)2=4925\left(\frac{5}{7}\right)^{-2} = \left(\frac{7}{5}\right)^2 = \frac{49}{25}

(b) Take the reciprocal of the fraction and change the sign of the exponent, then simplify:

(2xy)3=(y2x)3=y38x3\left(-\frac{2x}{y}\right)^{-3} = \left(-\frac{y}{2x}\right)^3 = -\frac{y^3}{8x^3}

Simplify: 234\tfrac{2}{3}^{-4}.

Simplify: 353\tfrac{3}{5}^{-3}.

When simplifying an expression with exponents, we must be careful to correctly identify the base.

Example. Simplify: (a) (3)2(-3)^{-2} (b) 32-3^{-2} (c) (13)2\left(-\tfrac{1}{3}\right)^{-2} (d) (13)2-\left(\tfrac{1}{3}\right)^{-2}.

(a) Here the exponent applies to the base 3-3. Take the reciprocal of the base and change the sign of the exponent: (3)2=1(3)2=19(-3)^{-2} = \tfrac{1}{(-3)^2} = \tfrac{1}{9}.

(b) The expression 32-3^{-2} means “find the opposite of 323^{-2}.” Rewrite as a product with 1-1, then apply the negative exponent: 32=132=1132=19-3^{-2} = -1 \cdot 3^{-2} = -1 \cdot \tfrac{1}{3^2} = -\tfrac{1}{9}.

(c) Here the exponent applies to the base 13-\tfrac{1}{3}. Take the reciprocal of the base and change the sign of the exponent: (13)2=(31)2=9\left(-\tfrac{1}{3}\right)^{-2} = \left(-\tfrac{3}{1}\right)^2 = 9.

(d) The expression (13)2-\left(\tfrac{1}{3}\right)^{-2} means “find the opposite of (13)2\left(\tfrac{1}{3}\right)^{-2}”: (13)2=1(31)2=9-\left(\tfrac{1}{3}\right)^{-2} = -1 \cdot \left(\tfrac{3}{1}\right)^2 = -9.

Simplify: (5)2(-5)^{-2}.

Simplify: 52-5^{-2}.

We must be careful to follow the Order of Operations. In the next example, parts (a) and (b) look similar, but the results are different.

Example. Simplify: (a) 4214 \cdot 2^{-1} (b) (42)1(4 \cdot 2)^{-1}.

(a) Do exponents before multiplication. Use an=1ana^{-n} = \tfrac{1}{a^n}, then simplify: 421=4121=24 \cdot 2^{-1} = 4 \cdot \tfrac{1}{2^1} = 2.

(b) Simplify inside the parentheses first, then apply the negative exponent: (42)1=(8)1=181=18(4 \cdot 2)^{-1} = (8)^{-1} = \tfrac{1}{8^1} = \tfrac{1}{8}.

Simplify: 6316 \cdot 3^{-1}.

Simplify: (63)1(6 \cdot 3)^{-1}.

When a variable is raised to a negative exponent, we apply the definition the same way we did with numbers. We will assume all variables are non-zero.

Example. Simplify: (a) x6x^{-6} (b) (u4)3\left(u^4\right)^{-3}.

(a) Use the definition of a negative exponent, an=1ana^{-n} = \tfrac{1}{a^n}: x6=1x6x^{-6} = \tfrac{1}{x^6}.

(b) Use the definition of a negative exponent, then simplify: (u4)3=1(u4)3=1u12\left(u^4\right)^{-3} = \tfrac{1}{\left(u^4\right)^3} = \tfrac{1}{u^{12}}.

Simplify: y7y^{-7}. Write the answer with a positive exponent.

Simplify: (z3)5(z^3)^{-5}. Write the answer with a positive exponent.

When there is a product and an exponent, we have to be careful to apply the exponent to the correct quantity. According to the Order of Operations, we simplify expressions in parentheses before applying exponents.

Example. Simplify: (a) 5y15y^{-1} (b) (5y)1(5y)^{-1} (c) (5y)1(-5y)^{-1}.

(a) Notice the exponent applies to just the base yy. Take the reciprocal of yy and change the sign of the exponent: 5y1=51y1=5y5y^{-1} = 5 \cdot \tfrac{1}{y^1} = \tfrac{5}{y}.

(b) Here the parentheses make the exponent apply to the base 5y5y. Take the reciprocal of 5y5y and change the sign of the exponent: (5y)1=1(5y)1=15y(5y)^{-1} = \tfrac{1}{(5y)^1} = \tfrac{1}{5y}.

(c) The base here is 5y-5y. Take the reciprocal of 5y-5y and change the sign of the exponent, then simplify: (5y)1=1(5y)1=15y=15y(-5y)^{-1} = \tfrac{1}{(-5y)^1} = \tfrac{1}{-5y} = -\tfrac{1}{5y}.

Simplify: 8p18p^{-1}. Write the answer with a positive exponent.

Simplify: (8p)1(8p)^{-1}. Write the answer with a positive exponent.

With negative exponents, the Quotient Rule needs only one form aman=amn\tfrac{a^m}{a^n} = a^{m-n}, for a0a \neq 0. When the exponent in the denominator is larger than the exponent in the numerator, the exponent of the quotient will be negative.

Simplify Expressions with Integer Exponents

All of the exponent properties we developed earlier in the chapter with whole number exponents apply to integer exponents, too. We restate them here for reference.

Summary of Exponent Properties. If aa and bb are real numbers, and mm and nn are integers, then

  • Product Property: aman=am+na^m \cdot a^n = a^{m+n}
  • Power Property: (am)n=amn\left(a^m\right)^n = a^{m \cdot n}
  • Product to a Power: (ab)m=ambm(ab)^m = a^m b^m
  • Quotient Property: aman=amn, a0\tfrac{a^m}{a^n} = a^{m-n},\ a \neq 0
  • Zero Exponent Property: a0=1, a0a^0 = 1,\ a \neq 0
  • Quotient to a Power Property: (ab)m=ambm, b0\left(\tfrac{a}{b}\right)^m = \tfrac{a^m}{b^m},\ b \neq 0
  • Property of Negative Exponents: an=1ana^{-n} = \tfrac{1}{a^n} and 1an=an\tfrac{1}{a^{-n}} = a^n
  • Quotient to a Negative Exponent: (ab)n=(ba)n\left(\tfrac{a}{b}\right)^{-n} = \left(\tfrac{b}{a}\right)^n

Example. Simplify: (a) x4x6x^{-4} \cdot x^6 (b) y6y4y^{-6} \cdot y^4 (c) z5z3z^{-5} \cdot z^{-3}.

(a) Use the Product Property, aman=am+na^m \cdot a^n = a^{m+n}: x4x6=x4+6=x2x^{-4} \cdot x^6 = x^{-4+6} = x^2.

(b) The bases are the same, so add the exponents: y6y4=y6+4=y2=1y2y^{-6} \cdot y^4 = y^{-6+4} = y^{-2} = \tfrac{1}{y^2}.

(c) Add the exponents, then apply the definition of a negative exponent: z5z3=z53=z8=1z8z^{-5} \cdot z^{-3} = z^{-5-3} = z^{-8} = \tfrac{1}{z^8}.

Simplify: x3x7x^{-3} \cdot x^7. Write the answer as a power of x.

Simplify: y7y2y^{-7} \cdot y^2. Write the answer with a positive exponent.

In the next two examples, we’ll start by using the Commutative Property to group the same variables together. This makes it easier to identify the like bases before using the Product Property.

Example. Simplify: (m4n3)(m5n2)\left(m^4 n^{-3}\right)\left(m^{-5} n^{-2}\right).

Use the Commutative Property to get like bases together, add the exponents for each base, then take reciprocals and change the signs of the exponents:

(m4n3)(m5n2)=m4m5n2n3=m1n5=1m11n5=1mn5 \left(m^4 n^{-3}\right)\left(m^{-5} n^{-2}\right) = m^4 m^{-5} \cdot n^{-2} n^{-3} = m^{-1} \cdot n^{-5} = \frac{1}{m^1} \cdot \frac{1}{n^5} = \frac{1}{mn^5}

Simplify: (p6q2)(p9q1)(p^6 q^{-2})(p^{-9} q^{-1}). Write the answer with positive exponents.

Simplify: (r5s3)(r7s5)(r^5 s^{-3})(r^{-7} s^{-5}). Write the answer with positive exponents.

In the next two examples, we’ll use the Power Property and the Product to a Power Property.

Example. Simplify: (6k3)2\left(6k^3\right)^{-2}.

Use the Product to a Power Property, then the Power Property, then the definition of a negative exponent, then simplify:

(6k3)2=(6)2(k3)2=62k6=1621k6=136k6 \left(6k^3\right)^{-2} = (6)^{-2}\left(k^3\right)^{-2} = 6^{-2} k^{-6} = \frac{1}{6^2} \cdot \frac{1}{k^6} = \frac{1}{36k^6}

Simplify: (4x4)2(-4x^4)^{-2}. Write the answer with positive exponents.

Example. Simplify: (5x3)2\left(5x^{-3}\right)^2.

Use the Product to a Power Property, simplify 525^2 and multiply the exponents of xx using the Power Property, then rewrite x6x^{-6} with the definition of a negative exponent:

(5x3)2=52(x3)2=25x6=251x6=25x6 \left(5x^{-3}\right)^2 = 5^2\left(x^{-3}\right)^2 = 25 \cdot x^{-6} = 25 \cdot \frac{1}{x^6} = \frac{25}{x^6}

Simplify: (8a4)2(8a^{-4})^2. Write the answer with positive exponents.

To simplify a fraction, we use the Quotient Property and subtract the exponents.

Example. Simplify: r5r4\tfrac{r^5}{r^{-4}}.

Use the Quotient Property, aman=amn\tfrac{a^m}{a^n} = a^{m-n}, then simplify:

r5r4=r5(4)=r9\frac{r^5}{r^{-4}} = r^{5-(-4)} = r^9

Simplify: x8/x3x^8 / x^{-3}. Write the answer as a power of x.

Simplify: y8/y6y^8 / y^{-6}. Write the answer as a power of y.

Convert from Decimal Notation to Scientific Notation

Remember working with place value for whole numbers and decimals? Our number system is based on powers of 1010. Consider the numbers 4,0004{,}000 and 0.0040.004. We know that 4,0004{,}000 means 4×1,0004 \times 1{,}000 and 0.0040.004 means 4×11,0004 \times \tfrac{1}{1{,}000}. If we write the 1,0001{,}000 as a power of ten in exponential form, we can rewrite these numbers this way:

4,000=4×1,000=4×1034{,}000 = 4 \times 1{,}000 = 4 \times 10^3

0.004=4×11,000=4×1103=4×1030.004 = 4 \times \frac{1}{1{,}000} = 4 \times \frac{1}{10^3} = 4 \times 10^{-3}

When a number is written as a product of two numbers, where the first factor is a number greater than or equal to one but less than ten, and the second factor is a power of 1010 written in exponential form, it is said to be in scientific notation.

Scientific Notation. A number is expressed in scientific notation when it is of the form

a×10n where 1a<10 and n is an integer.a \times 10^n \text{ where } 1 \le |a| < 10 \text{ and } n \text{ is an integer.}

It is customary in scientific notation to use ×\times as the multiplication sign, even though we avoid using this sign elsewhere in algebra.

If we look at what happened to the decimal point, we can see a method to easily convert from decimal notation to scientific notation. In 4,0004{,}000, the decimal was moved 33 places to the left; in 0.0040.004, it was moved 33 places to the right. In both cases, the decimal was moved 33 places to get the first factor between 11 and 1010. The power of 1010 is positive when the number is larger than 11, and negative when the number is between 00 and 11.

Convert from decimal notation to scientific notation.

  1. Move the decimal point so that the first factor is greater than or equal to 11 but less than 1010.
  2. Count the number of decimal places, nn, that the decimal point was moved.
  3. Write the number as a product with a power of 1010. If the original number is greater than 11, the power of 1010 will be 10n10^n; if it is between 00 and 11, the power of 1010 will be 10n10^{-n}.
  4. Check.

Example. Write in scientific notation: 37,00037{,}000.

Move the decimal point after the 33 so the first factor, 3.73.7, is between 11 and 1010. The decimal point was moved 44 places to the left. Since 37,00037{,}000 is greater than 11, the power of 1010 will have exponent 44:

37,000=3.7×10437{,}000 = 3.7 \times 10^4

Check: 10410^4 is 10,00010{,}000, and 10,00010{,}000 times 3.73.7 is 37,00037{,}000. ✓

Write in scientific notation: 96,000.

Write in scientific notation: 48,300.

Example. Write in scientific notation: 0.00520.0052.

The original number, 0.00520.0052, is between 00 and 11, so we will have a negative power of 1010. Move the decimal point to get 5.25.2, a number between 11 and 1010. The decimal point was moved 33 places to the right:

0.0052=5.2×1030.0052 = 5.2 \times 10^{-3}

Check: 5.2×103=5.2×11000=5.2×0.001=0.00525.2 \times 10^{-3} = 5.2 \times \tfrac{1}{1000} = 5.2 \times 0.001 = 0.0052. ✓

Write in scientific notation: 0.0078.

Write in scientific notation: 0.0129.

Convert Scientific Notation to Decimal Form

How can we convert from scientific notation to decimal form? Let’s look at two numbers written in scientific notation and see.

9.12×104=9.12×10,000=91,2009.12 \times 10^4 = 9.12 \times 10{,}000 = 91{,}200

9.12×104=9.12×0.0001=0.0009129.12 \times 10^{-4} = 9.12 \times 0.0001 = 0.000912

If we look at the location of the decimal point, we can see an easy method to convert a number from scientific notation to decimal form. When the exponent was positive, the decimal moved 44 places to the right; when the exponent was negative, the decimal moved 44 places to the left.

Convert scientific notation to decimal form.

  1. Determine the exponent, nn, on the factor 1010.
  2. Move the decimal nn places, adding zeros if needed. If the exponent is positive, move the decimal point nn places to the right; if the exponent is negative, move the decimal point n|n| places to the left.
  3. Check.

Example. Convert to decimal form: 6.2×1036.2 \times 10^3.

The exponent is 33, and it is positive, so move the decimal point 33 places to the right. We need to add 22 zeros as placeholders:

6.2×103=6,2006.2 \times 10^3 = 6{,}200

Check: 10310^3 is 10001000, and 10001000 times 6.26.2 will be 6,2006{,}200. ✓

Convert to decimal form: 1.3×1031.3 \times 10^3.

Convert to decimal form: 9.25×1049.25 \times 10^4.

Example. Convert to decimal form: 8.9×1028.9 \times 10^{-2}.

The exponent is 2-2. Since it is negative, move the decimal point 22 places to the left, adding zeros as needed for placeholders:

8.9×102=0.0898.9 \times 10^{-2} = 0.089

Convert to decimal form: 1.2×1041.2 \times 10^{-4}.

Convert to decimal form: 7.5×1027.5 \times 10^{-2}.

Multiply and Divide Using Scientific Notation

Astronomers use very large numbers to describe distances in the universe and ages of stars and planets. Chemists use very small numbers to describe the size of an atom or the charge on an electron. When scientists perform calculations with very large or very small numbers, they use scientific notation. Scientific notation provides a way for the calculations to be done without writing a lot of zeros. We will see how the Properties of Exponents are used to multiply and divide numbers in scientific notation.

Example. Multiply. Write answers in decimal form: (4×105)(2×107)\left(4 \times 10^5\right)\left(2 \times 10^{-7}\right).

Use the Commutative Property to rearrange the factors, multiply, then change to decimal form:

(4×105)(2×107)=42105107=8×102=0.08 \left(4 \times 10^5\right)\left(2 \times 10^{-7}\right) = 4 \cdot 2 \cdot 10^5 \cdot 10^{-7} = 8 \times 10^{-2} = 0.08

Multiply (3×106)(2×108)(3 \times 10^6)(2 \times 10^{-8}). Write the answer in decimal form.

Multiply (3×102)(3×101)(3 \times 10^{-2})(3 \times 10^{-1}). Write the answer in decimal form.

Example. Divide. Write answers in decimal form: 9×1033×102\tfrac{9 \times 10^3}{3 \times 10^{-2}}.

Separate the factors, rewriting as the product of two fractions, divide, then change to decimal form:

9×1033×102=93×103102=3×105=300,000 \frac{9 \times 10^3}{3 \times 10^{-2}} = \frac{9}{3} \times \frac{10^3}{10^{-2}} = 3 \times 10^5 = 300{,}000

Divide 8×1042×101\tfrac{8 \times 10^4}{2 \times 10^{-1}}. Write the answer in decimal form.

Divide 8×1024×102\tfrac{8 \times 10^2}{4 \times 10^{-2}}. Write the answer in decimal form.

Key terms

negative exponent — for a0a \neq 0, an=1ana^{-n} = \tfrac{1}{a^n}; a negative exponent means take the reciprocal of the base and change the sign of the exponent. Property of Negative Exponents1an=an\tfrac{1}{a^{-n}} = a^n. Quotient to a Negative Exponent Property(ab)n=(ba)n\left(\tfrac{a}{b}\right)^{-n} = \left(\tfrac{b}{a}\right)^n. scientific notation — a number written in the form a×10na \times 10^n, where 1a<101 \le |a| < 10 and nn is an integer; the power of 1010 is positive for numbers larger than 11 and negative for numbers between 00 and 11.


This section is adapted from Elementary Algebra 2e, Section 6.7: Integer Exponents and Scientific Notation by Lynn Marecek, MaryAnne Anthony-Smith, and Andrea Honeycutt Mathis, © OpenStax, licensed under CC BY-NC-SA 4.0. Access the original for free at openstax.org. Changes: recast the worked-example step tables as prose and typeset equations; omitted the Be Prepared quiz, Self Check checklist, media links, and end-of-section exercises; and converted the practice problems (“Try Its”) into interactive exercises with instant feedback.