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Simplify and Use Square Roots

Simplify and Use Square Roots

By the end of this section, you will be able to: simplify expressions with square roots, estimate square roots, approximate square roots, and simplify variable expressions with square roots.

Simplify Expressions with Square Roots

Remember that when a number nn is multiplied by itself, we write n2n^2 and read it “nn squared.” For example, 15215^2 reads as “1515 squared,” and 225225 is called the square of 1515, since 152=22515^2 = 225.

Square of a number. If n2=mn^2 = m, then mm is the square of nn.

Sometimes we need to look at the relationship between numbers and their squares in reverse. Because 225225 is the square of 1515, we can also say that 1515 is a square root of 225225. A number whose square is mm is called a square root of mm.

Square root of a number. If n2=mn^2 = m, then nn is a square root of mm.

Notice that (15)2=225(-15)^2 = 225 also, so 15-15 is also a square root of 225225. Therefore, both 1515 and 15-15 are square roots of 225225.

So every positive number has two square roots — one positive and one negative. What if we only wanted the positive square root of a positive number? The radical sign, m\sqrt{m}, denotes the positive square root. The positive square root is also called the principal square root.

We also use the radical sign for the square root of zero. Because 02=00^2 = 0, 0=0\sqrt{0} = 0. Notice that zero has only one square root.

Square root notation. In m\sqrt{m}, the m\sqrt{\phantom{m}} is the radical sign and mm is the radicand. m\sqrt{m} is read “the square root of mm.” If m=n2m = n^2, then m=n\sqrt{m} = n, for n0n \geq 0. The square root of mm, m\sqrt{m}, is the non-negative number whose square is mm.

Since 1515 is the positive square root of 225225, we write 225=15\sqrt{225} = 15. The radical sign indicates the positive root, so 225=15\sqrt{225} = 15. If we want the negative square root of a number, we place a negative sign in front of the radical sign. For example, 225=15-\sqrt{225} = -15.

Example. Simplify: (a) 36\sqrt{36}, (b) 196\sqrt{196}, (c) 81-\sqrt{81}, (d) 289-\sqrt{289}.

(a) Since 62=36.36=6(b) Since 142=196.196=14(c) The negative is in front of the radical sign.81=9(d) The negative is in front of the radical sign.289=17 \begin{array}{lrcl} \text{(a) Since } 6^2 = 36. & \sqrt{36} &=& 6 \\[4pt] \text{(b) Since } 14^2 = 196. & \sqrt{196} &=& 14 \\[4pt] \text{(c) The negative is in front of the radical sign.} & -\sqrt{81} &=& -9 \\[4pt] \text{(d) The negative is in front of the radical sign.} & -\sqrt{289} &=& -17 \end{array}

Can we simplify 169\sqrt{-169}? Is there a number whose square is 169-169? Any positive number squared is positive, and any negative number squared is also positive. There is no real number equal to 169\sqrt{-169}, so we say 169\sqrt{-169} is not a real number. Contrast this with 64=8-\sqrt{64} = -8, where the negative sits outside the radical.

Simplify 225\sqrt{225}.

Simplify 121-\sqrt{121}.

Which is true of 196\sqrt{-196}?

When using the order of operations to simplify an expression that has square roots, we treat the radical as a grouping symbol.

Example. Simplify: (a) 25+144\sqrt{25} + \sqrt{144}, (b) 25+144\sqrt{25 + 144}.

(a) Use the order of operations.25+144=5+12Simplify.=17(b) Simplify under the radical sign.25+144=169Simplify.=13 \begin{array}{lrcl} \text{(a) Use the order of operations.} & \sqrt{25} + \sqrt{144} &=& 5 + 12 \\[4pt] \text{Simplify.} & &=& 17 \\[4pt] \text{(b) Simplify under the radical sign.} & \sqrt{25 + 144} &=& \sqrt{169} \\[4pt] \text{Simplify.} & &=& 13 \end{array}

Notice the different answers in parts (a) and (b)!

Simplify 9+16\sqrt{9} + \sqrt{16}.

Simplify 64+225\sqrt{64 + 225}.

Estimate Square Roots

So far we have only considered square roots of perfect square numbers. The square roots of other numbers are not whole numbers. Consider the perfect squares 44 and 99: since 4=2\sqrt{4} = 2 and 9=3\sqrt{9} = 3, any number between 44 and 99 has a square root between 22 and 33. For example, 5\sqrt{5} must be between 22 and 33. Using inequality symbols, we write:

2<5<3 2 < \sqrt{5} < 3

Example. Estimate 60\sqrt{60} between two consecutive whole numbers.

Think of the perfect square numbers closest to 6060. The perfect squares just below and above 6060 are 49=7249 = 7^2 and 64=8264 = 8^2.

Locate 60 between two consecutive perfect squares.49<60<6460 is between their square roots.7<60<8 \begin{array}{lrcl} \text{Locate } 60 \text{ between two consecutive perfect squares.} & 49 &<& 60 < 64 \\[4pt] \sqrt{60} \text{ is between their square roots.} & 7 &<& \sqrt{60} < 8 \end{array}

Estimate 38\sqrt{38}: it lies between two consecutive whole numbers. Enter the smaller whole number.

Estimate 84\sqrt{84}: it lies between two consecutive whole numbers. Enter the larger whole number.

Approximate Square Roots

There are mathematical methods to approximate square roots, but nowadays most people use a calculator to find them. Find the x\sqrt{x} key on your calculator; you will use this key to approximate square roots.

When you use your calculator to find the square root of a number that is not a perfect square, the answer you see is not the exact square root. It is an approximation, accurate to the number of digits shown on your calculator’s display. The symbol for an approximation is \approx and it is read “approximately.”

Suppose your calculator has a 1010-digit display. You would see that 52.236067978\sqrt{5} \approx 2.236067978. If we wanted to round 5\sqrt{5} to two decimal places, we would say 52.24\sqrt{5} \approx 2.24.

How do we know these values are approximations and not the exact values? Look at what happens when we square them:

(2.236067978)2=5.000000002(2.24)2=5.0176 \begin{array}{rcl} (2.236067978)^2 &=& 5.000000002 \\[4pt] (2.24)^2 &=& 5.0176 \end{array}

Their squares are close to 55, but are not exactly equal to 55.

Example. Round 17\sqrt{17} to two decimal places.

Use the calculator square root key.174.123105626Round to two decimal places.174.12 \begin{array}{lrcl} \text{Use the calculator square root key.} & \sqrt{17} &\approx& 4.123105626\ldots \\[4pt] \text{Round to two decimal places.} & \sqrt{17} &\approx& 4.12 \end{array}

Round 11\sqrt{11} to two decimal places.

Round 13\sqrt{13} to two decimal places.

Simplify Variable Expressions with Square Roots

What if we have to find a square root of an expression with a variable? Consider 9x2\sqrt{9x^2}. Can you think of an expression whose square is 9x29x^2? Since (3x)2=9x2(3x)^2 = 9x^2, we have 9x2=3x\sqrt{9x^2} = 3x.

When we use the radical sign to take the square root of a variable expression, we should specify that x0x \geq 0 to make sure we get the principal square root. However, in this chapter we will assume that each variable in a square-root expression represents a non-negative number, and so we will not write x0x \geq 0 next to every radical.

What about square roots of higher powers of variables? Think about the Power Property of Exponents, (am)n=amn\left(a^m\right)^n = a^{m \cdot n}. If we square ama^m, the exponent will become 2m2m:

(am)2=a2m \left(a^m\right)^2 = a^{2m}

This tells us how to take square roots of even powers. For example, 25u8=5u4\sqrt{25u^8} = 5u^4 because (5u4)2=25u8\left(5u^4\right)^2 = 25u^8, and 196q36=14q18\sqrt{196q^{36}} = 14q^{18} because (14q18)2=196q36\left(14q^{18}\right)^2 = 196q^{36}.

Example. Simplify: (a) x6\sqrt{x^6}, (b) y16\sqrt{y^{16}}.

(a) Since (x3)2=x6.x6=x3(b) Since (y8)2=y16.y16=y8 \begin{array}{lrcl} \text{(a) Since } \left(x^3\right)^2 = x^6. & \sqrt{x^6} &=& x^3 \\[4pt] \text{(b) Since } \left(y^8\right)^2 = y^{16}. & \sqrt{y^{16}} &=& y^8 \end{array}

Example. Simplify 16n2\sqrt{16n^2}.

Since (4n)2=16n2.16n2=4n \begin{array}{lrcl} \text{Since } (4n)^2 = 16n^2. & \sqrt{16n^2} &=& 4n \end{array}

Example. Simplify 81c2-\sqrt{81c^2}.

Since (9c)2=81c2.81c2=9c \begin{array}{lrcl} \text{Since } (9c)^2 = 81c^2. & -\sqrt{81c^2} &=& -9c \end{array}

Example. Simplify 36x2y2\sqrt{36x^2y^2}.

Since (6xy)2=36x2y2.36x2y2=6xy \begin{array}{lrcl} \text{Since } (6xy)^2 = 36x^2y^2. & \sqrt{36x^2y^2} &=& 6xy \end{array}

Example. Simplify 64p64\sqrt{64p^{64}}.

Since (8p32)2=64p64.64p64=8p32 \begin{array}{lrcl} \text{Since } \left(8p^{32}\right)^2 = 64p^{64}. & \sqrt{64p^{64}} &=& 8p^{32} \end{array}

Example. Simplify 121a6b8\sqrt{121a^6b^8}.

Since (11a3b4)2=121a6b8.121a6b8=11a3b4 \begin{array}{lrcl} \text{Since } \left(11a^3b^4\right)^2 = 121a^6b^8. & \sqrt{121a^6b^8} &=& 11a^3b^4 \end{array}

Simplify z12\sqrt{z^{12}}.

Simplify 64x2\sqrt{64x^2}.

Simplify 100p2-\sqrt{100p^2}.

Key terms

square of a number — if n2=mn^2 = m, then mm is the square of nn. square root of a number — if n2=mn^2 = m, then nn is a square root of mm; every positive number has two square roots, one positive and one negative. radical sign — the symbol m\sqrt{\phantom{m}} that denotes the positive (principal) square root. radicand — the number or expression under the radical sign. principal square root — the non-negative square root, the one the radical sign indicates. approximation — a value close to the exact square root, written with \approx, accurate to the number of digits displayed.


This section is adapted from Elementary Algebra 2e, 9.1 Simplify and Use Square Roots by Lynn Marecek, MaryAnne Anthony-Smith, and Andrea Honeycutt Mathis, © OpenStax, licensed under CC BY-NC-SA 4.0. Access the original for free at openstax.org. Changes: recast the two-column worked examples as aligned step tables; omitted the Be Prepared quiz, media links, and end-of-section exercises; and converted the practice problems (“Try Its”) into interactive exercises with instant feedback.