Skip to content

Rational Exponents

By the end of this section, you will be able to: simplify expressions with a1/na^{1/n}; simplify expressions with am/na^{m/n}; and use the laws of exponents to simplify expressions with rational exponents.

Simplify expressions with a1/na^{1/n}

Rational exponents are another way of writing expressions with radicals. When we use rational exponents, we can apply the properties of exponents to simplify expressions.

The Power Property for Exponents says that (am)n=amn\left(a^m\right)^n = a^{m \cdot n} when mm and nn are whole numbers. Let’s assume we are now not limited to whole numbers.

Suppose we want to find a number pp such that (8p)3=8\left(8^p\right)^3 = 8. We will use the Power Property of Exponents to find the value of pp:

(8p)3=8Multiply the exponents on the left.83p=8Write the exponent 1 on the right.83p=81The exponents must be equal.3p=1Solve for p.p=13 \begin{array}{lrcl} & \left(8^p\right)^3 &=& 8 \\[4pt] \text{Multiply the exponents on the left.} & 8^{3p} &=& 8 \\[4pt] \text{Write the exponent } 1 \text{ on the right.} & 8^{3p} &=& 8^1 \\[4pt] \text{The exponents must be equal.} & 3p &=& 1 \\[4pt] \text{Solve for } p. & p &=& \tfrac{1}{3} \end{array}

So (81/3)3=8\left(8^{1/3}\right)^3 = 8. But we know also that (83)3=8\left(\sqrt[3]{8}\right)^3 = 8. Then it must be that 81/3=838^{1/3} = \sqrt[3]{8}.

This same logic can be used for any positive integer exponent nn to show that a1/n=ana^{1/n} = \sqrt[n]{a}.

Rational Exponent a1/na^{1/n}. If an\sqrt[n]{a} is a real number and n2n \geq 2, then

a1/n=an. a^{1/n} = \sqrt[n]{a}.

There will be times when working with expressions will be easier if you use rational exponents, and times when it will be easier if you use radicals. In the first few examples, you’ll practice converting expressions between these two notations.

Example. Write as a radical expression: (a) x1/2x^{1/2}, (b) y1/3y^{1/3}, (c) z1/4z^{1/4}.

We want to write each expression in the form an\sqrt[n]{a}. The denominator of the rational exponent is the index of the radical:

(a) The denominator is 2, so the index is 2.x1/2=x(b) The denominator is 3, so the index is 3.y1/3=y3(c) The denominator is 4, so the index is 4.z1/4=z4 \begin{array}{lrcl} \text{(a) The denominator is } 2, \text{ so the index is } 2. & x^{1/2} &=& \sqrt{x} \\[4pt] \text{(b) The denominator is } 3, \text{ so the index is } 3. & y^{1/3} &=& \sqrt[3]{y} \\[4pt] \text{(c) The denominator is } 4, \text{ so the index is } 4. & z^{1/4} &=& \sqrt[4]{z} \end{array}

We do not show the index when it is 22.

Write t1/2t^{1/2} as a radical expression.

Example. Write with a rational exponent: (a) x\sqrt{x}, (b) y3\sqrt[3]{y}, (c) z4\sqrt[4]{z}.

We want to write each radical in the form a1/na^{1/n}. The index of the radical becomes the denominator of the rational exponent:

(a) No index is shown, so it is 2.x=x1/2(b) The index is 3.y3=y1/3(c) The index is 4.z4=z1/4 \begin{array}{lrcl} \text{(a) No index is shown, so it is } 2. & \sqrt{x} &=& x^{1/2} \\[4pt] \text{(b) The index is } 3. & \sqrt[3]{y} &=& y^{1/3} \\[4pt] \text{(c) The index is } 4. & \sqrt[4]{z} &=& z^{1/4} \end{array}

Write p3\sqrt[3]{p} with a rational exponent.

Example. Write with a rational exponent: (a) 5y\sqrt{5y}, (b) 4x3\sqrt[3]{4x}, (c) 35z43\sqrt[4]{5z}.

The entire radicand becomes the base. Note in part (c) that the factor 33 is not under the radical, so it stays outside:

(a) No index is shown, so it is 2.5y=(5y)1/2(b) The index is 3.4x3=(4x)1/3(c) The index is 4.35z4=3(5z)1/4 \begin{array}{lrcl} \text{(a) No index is shown, so it is } 2. & \sqrt{5y} &=& (5y)^{1/2} \\[4pt] \text{(b) The index is } 3. & \sqrt[3]{4x} &=& (4x)^{1/3} \\[4pt] \text{(c) The index is } 4. & 3\sqrt[4]{5z} &=& 3(5z)^{1/4} \end{array}

Write 3n3\sqrt[3]{3n} with a rational exponent.

In the next example, you may find it easier to simplify the expressions if you rewrite them as radicals first.

Example. Simplify: (a) 251/225^{1/2}, (b) 641/364^{1/3}, (c) 2561/4256^{1/4}.

Rewrite each as a radical, then recognize the perfect power and simplify:

(a) Rewrite as a square root, then simplify.251/2=25=5(b) Rewrite as a cube root; 64=43.641/3=433=4(c) Rewrite as a fourth root; 256=44.2561/4=444=4 \begin{array}{lrcl} \text{(a) Rewrite as a square root, then simplify.} & 25^{1/2} &=& \sqrt{25} = 5 \\[4pt] \text{(b) Rewrite as a cube root; } 64 = 4^3. & 64^{1/3} &=& \sqrt[3]{4^3} = 4 \\[4pt] \text{(c) Rewrite as a fourth root; } 256 = 4^4. & 256^{1/4} &=& \sqrt[4]{4^4} = 4 \end{array}

Simplify: 361/236^{1/2}.

Simplify: 81/38^{1/3}.

Be careful of the placement of the negative signs in the next example. We will need to use the property an=1ana^{-n} = \tfrac{1}{a^n} in one case.

Example. Simplify: (a) (64)1/3(-64)^{1/3}, (b) 641/3-64^{1/3}, (c) (64)1/3(64)^{-1/3}.

(a) Rewrite 64=(4)3, then simplify.(64)1/3=(4)33=4(b) The exponent applies only to the 64.641/3=433=4(c) Rewrite with a positive exponent, an=1an.(64)1/3=1433=14 \begin{array}{lrcl} \text{(a) Rewrite } -64 = (-4)^3, \text{ then simplify.} & (-64)^{1/3} &=& \sqrt[3]{(-4)^3} = -4 \\[4pt] \text{(b) The exponent applies only to the } 64. & -64^{1/3} &=& -\sqrt[3]{4^3} = -4 \\[4pt] \text{(c) Rewrite with a positive exponent, } a^{-n} = \tfrac{1}{a^n}. & (64)^{-1/3} &=& \tfrac{1}{\sqrt[3]{4^3}} = \tfrac{1}{4} \end{array}

Simplify: (125)1/3(-125)^{1/3}.

Simplify: (125)1/3(125)^{-1/3}.

Example. Simplify: (a) (16)1/4(-16)^{1/4}, (b) 161/4-16^{1/4}, (c) (16)1/4(16)^{-1/4}.

(a) There is no real number whose fourth power is 16.(16)1/4not a real number(b) The exponent applies only to the 16.161/4=244=2(c) Rewrite with a positive exponent, then simplify.(16)1/4=1244=12 \begin{array}{lrcl} \text{(a) There is no real number whose fourth power is } -16. & (-16)^{1/4} & & \text{not a real number} \\[4pt] \text{(b) The exponent applies only to the } 16. & -16^{1/4} &=& -\sqrt[4]{2^4} = -2 \\[4pt] \text{(c) Rewrite with a positive exponent, then simplify.} & (16)^{-1/4} &=& \tfrac{1}{\sqrt[4]{2^4}} = \tfrac{1}{2} \end{array}

Simplify: 161/2-16^{1/2}.

Simplify: (64)1/2(64)^{-1/2}.

Simplify expressions with am/na^{m/n}

Let’s work with the Power Property for Exponents some more. Suppose we raise a1/na^{1/n} to the power mm:

(a1/n)m=a(1/n)m=am/n \left(a^{1/n}\right)^m = a^{(1/n) \cdot m} = a^{m/n}

So am/n=(an)ma^{m/n} = \left(\sqrt[n]{a}\right)^m. Now suppose we take ama^m to the 1n\tfrac{1}{n} power:

(am)1/n=am(1/n)=am/n \left(a^m\right)^{1/n} = a^{m \cdot (1/n)} = a^{m/n}

So am/n=amna^{m/n} = \sqrt[n]{a^m} also. Which form do we use to simplify an expression? We usually take the root first — that way we keep the numbers in the radicand smaller.

Rational Exponent am/na^{m/n}. For any positive integers mm and nn,

am/n=(an)mandam/n=amn. a^{m/n} = \left(\sqrt[n]{a}\right)^m \qquad \text{and} \qquad a^{m/n} = \sqrt[n]{a^m}.

Example. Write with a rational exponent: (a) y3\sqrt{y^3}, (b) x23\sqrt[3]{x^2}, (c) z34\sqrt[4]{z^3}.

We use am/n=amna^{m/n} = \sqrt[n]{a^m}: the exponent in the radicand is the numerator, and the index is the denominator:

(a) Numerator 3, index 2.y3=y3/2(b) Numerator 2, index 3.x23=x2/3(c) Numerator 3, index 4.z34=z3/4 \begin{array}{lrcl} \text{(a) Numerator } 3, \text{ index } 2. & \sqrt{y^3} &=& y^{3/2} \\[4pt] \text{(b) Numerator } 2, \text{ index } 3. & \sqrt[3]{x^2} &=& x^{2/3} \\[4pt] \text{(c) Numerator } 3, \text{ index } 4. & \sqrt[4]{z^3} &=& z^{3/4} \end{array}

Write z34\sqrt[4]{z^3} with a rational exponent.

Example. Simplify: (a) 93/29^{3/2}, (b) 1252/3125^{2/3}, (c) 813/481^{3/4}.

We rewrite each expression as a radical first using am/n=(an)ma^{m/n} = \left(\sqrt[n]{a}\right)^m. This form lets us take the root first, keeping the numbers in the radicand smaller:

(a)93/2=(9)3=33=27(b)1252/3=(1253)2=52=25(c)813/4=(814)3=33=27 \begin{array}{lrcl} \text{(a)} & 9^{3/2} &=& \left(\sqrt{9}\right)^3 = 3^3 = 27 \\[4pt] \text{(b)} & 125^{2/3} &=& \left(\sqrt[3]{125}\right)^2 = 5^2 = 25 \\[4pt] \text{(c)} & 81^{3/4} &=& \left(\sqrt[4]{81}\right)^3 = 3^3 = 27 \end{array}

Simplify: 43/24^{3/2}.

Simplify: 272/327^{2/3}.

Remember that bp=1bpb^{-p} = \tfrac{1}{b^p}. The negative sign in the exponent does not change the sign of the expression.

Example. Simplify: (a) 163/216^{-3/2}, (b) 322/532^{-2/5}, (c) 45/24^{-5/2}.

We rewrite each expression first using bp=1bpb^{-p} = \tfrac{1}{b^p} and then change to radical form:

(a)163/2=1163/2=1(16)3=143=164(b)322/5=1322/5=1(325)2=122=14(c)45/2=145/2=1(4)5=125=132 \begin{array}{lrcl} \text{(a)} & 16^{-3/2} &=& \tfrac{1}{16^{3/2}} = \tfrac{1}{\left(\sqrt{16}\right)^3} = \tfrac{1}{4^3} = \tfrac{1}{64} \\[10pt] \text{(b)} & 32^{-2/5} &=& \tfrac{1}{32^{2/5}} = \tfrac{1}{\left(\sqrt[5]{32}\right)^2} = \tfrac{1}{2^2} = \tfrac{1}{4} \\[10pt] \text{(c)} & 4^{-5/2} &=& \tfrac{1}{4^{5/2}} = \tfrac{1}{\left(\sqrt{4}\right)^5} = \tfrac{1}{2^5} = \tfrac{1}{32} \end{array}

Simplify: 163/416^{-3/4}.

Example. Simplify: (a) 253/2-25^{3/2}, (b) 253/2-25^{-3/2}, (c) (25)3/2(-25)^{3/2}.

(a) The exponent applies only to 25.253/2=(25)3=(5)3=125(b) Rewrite with a positive exponent first.253/2=1(25)3=1125(c) There is no real number whose square root is 25.(25)3/2not a real number \begin{array}{lrcl} \text{(a) The exponent applies only to } 25. & -25^{3/2} &=& -\left(\sqrt{25}\right)^3 = -(5)^3 = -125 \\[10pt] \text{(b) Rewrite with a positive exponent first.} & -25^{-3/2} &=& -\tfrac{1}{\left(\sqrt{25}\right)^3} = -\tfrac{1}{125} \\[10pt] \text{(c) There is no real number whose square root is } -25. & (-25)^{3/2} & & \text{not a real number} \end{array}

Simplify: 813/2-81^{3/2}.

Use the laws of exponents to simplify expressions with rational exponents

The same laws of exponents that we already used apply to rational exponents, too. We list the exponent properties here for reference as we simplify expressions.

Summary of Exponent Properties. If aa, bb are real numbers and mm, nn are rational numbers, then

  • Product Property: aman=am+na^m \cdot a^n = a^{m+n}
  • Power Property: (am)n=amn\left(a^m\right)^n = a^{m \cdot n}
  • Product to a Power: (ab)m=ambm(ab)^m = a^m b^m
  • Quotient Property: aman=amn, a0, m>n\tfrac{a^m}{a^n} = a^{m-n},\ a \neq 0,\ m > n and aman=1anm, a0, n>m\tfrac{a^m}{a^n} = \tfrac{1}{a^{n-m}},\ a \neq 0,\ n > m
  • Zero Exponent Definition: a0=1, a0a^0 = 1,\ a \neq 0
  • Quotient to a Power Property: (ab)m=ambm, b0\left(\tfrac{a}{b}\right)^m = \tfrac{a^m}{b^m},\ b \neq 0

When we multiply the same base, we add the exponents.

Example. Simplify: (a) 21/225/22^{1/2} \cdot 2^{5/2}, (b) x2/3x4/3x^{2/3} \cdot x^{4/3}, (c) z3/4z5/4z^{3/4} \cdot z^{5/4}.

The bases are the same, so we add the exponents:

(a)21/225/2=21/2+5/2=26/2=23=8(b)x2/3x4/3=x2/3+4/3=x6/3=x2(c)z3/4z5/4=z3/4+5/4=z8/4=z2 \begin{array}{lrcl} \text{(a)} & 2^{1/2} \cdot 2^{5/2} &=& 2^{1/2 + 5/2} = 2^{6/2} = 2^3 = 8 \\[4pt] \text{(b)} & x^{2/3} \cdot x^{4/3} &=& x^{2/3 + 4/3} = x^{6/3} = x^2 \\[4pt] \text{(c)} & z^{3/4} \cdot z^{5/4} &=& z^{3/4 + 5/4} = z^{8/4} = z^2 \end{array}

Simplify: y1/3y8/3y^{1/3} \cdot y^{8/3}. Write the answer with a rational or whole exponent.

We will use the Power Property in the next example.

Example. Simplify: (a) (x4)1/2\left(x^4\right)^{1/2}, (b) (y6)1/3\left(y^6\right)^{1/3}, (c) (z9)2/3\left(z^9\right)^{2/3}.

To raise a power to a power, we multiply the exponents:

(a)(x4)1/2=x41/2=x2(b)(y6)1/3=y61/3=y2(c)(z9)2/3=z92/3=z6 \begin{array}{lrcl} \text{(a)} & \left(x^4\right)^{1/2} &=& x^{4 \cdot 1/2} = x^2 \\[4pt] \text{(b)} & \left(y^6\right)^{1/3} &=& y^{6 \cdot 1/3} = y^2 \\[4pt] \text{(c)} & \left(z^9\right)^{2/3} &=& z^{9 \cdot 2/3} = z^6 \end{array}

Simplify: (p10)1/5\left(p^{10}\right)^{1/5}. Write the answer with a whole-number exponent.

The Quotient Property tells us that when we divide with the same base, we subtract the exponents.

Example. Simplify: (a) x4/3x1/3\tfrac{x^{4/3}}{x^{1/3}}, (b) y3/4y1/4\tfrac{y^{3/4}}{y^{1/4}}, (c) z2/3z5/3\tfrac{z^{2/3}}{z^{5/3}}.

To divide with the same base, we subtract the exponents:

(a)x4/3x1/3=x4/31/3=x3/3=x(b)y3/4y1/4=y3/41/4=y2/4=y1/2(c)z2/3z5/3=z2/35/3=z3/3=1z \begin{array}{lrcl} \text{(a)} & \tfrac{x^{4/3}}{x^{1/3}} &=& x^{4/3 - 1/3} = x^{3/3} = x \\[10pt] \text{(b)} & \tfrac{y^{3/4}}{y^{1/4}} &=& y^{3/4 - 1/4} = y^{2/4} = y^{1/2} \\[10pt] \text{(c)} & \tfrac{z^{2/3}}{z^{5/3}} &=& z^{2/3 - 5/3} = z^{-3/3} = \tfrac{1}{z} \end{array}

Simplify: u5/4u1/4\tfrac{u^{5/4}}{u^{1/4}}. Write the answer with a rational or whole exponent.

Sometimes we need to use more than one property. In the next examples, we will use both the Product to a Power Property and then the Power Property.

Example. Simplify: (a) (27u1/2)2/3\left(27u^{1/2}\right)^{2/3}, (b) (8v1/4)2/3\left(8v^{1/4}\right)^{2/3}.

First we use the Product to a Power Property, then the Power Property:

(a)(27u1/2)2/3=(27)2/3(u1/2)2/3=(33)2/3(u1/2)2/3=32u1/3=9u1/3(b)(8v1/4)2/3=(8)2/3(v1/4)2/3=(23)2/3(v1/4)2/3=22v1/6=4v1/6 \begin{array}{lrcl} \text{(a)} & \left(27u^{1/2}\right)^{2/3} &=& (27)^{2/3}\left(u^{1/2}\right)^{2/3} = \left(3^3\right)^{2/3}\left(u^{1/2}\right)^{2/3} = 3^2 u^{1/3} = 9u^{1/3} \\[10pt] \text{(b)} & \left(8v^{1/4}\right)^{2/3} &=& (8)^{2/3}\left(v^{1/4}\right)^{2/3} = \left(2^3\right)^{2/3}\left(v^{1/4}\right)^{2/3} = 2^2 v^{1/6} = 4v^{1/6} \end{array}

Simplify: (32x1/3)3/5\left(32x^{1/3}\right)^{3/5}.

Example. Simplify: (a) (m3n9)1/3\left(m^3 n^9\right)^{1/3}, (b) (p4q8)1/4\left(p^4 q^8\right)^{1/4}.

First we use the Product to a Power Property, then the Power Property:

(a)(m3n9)1/3=(m3)1/3(n9)1/3=mn3(b)(p4q8)1/4=(p4)1/4(q8)1/4=pq2 \begin{array}{lrcl} \text{(a)} & \left(m^3 n^9\right)^{1/3} &=& \left(m^3\right)^{1/3}\left(n^9\right)^{1/3} = m n^3 \\[4pt] \text{(b)} & \left(p^4 q^8\right)^{1/4} &=& \left(p^4\right)^{1/4}\left(q^8\right)^{1/4} = p q^2 \end{array}

Simplify: (m3n9)1/3\left(m^3 n^9\right)^{1/3}.

We will use both the Product and Quotient Properties in the next example.

Example. Simplify: (a) x3/4x1/4x6/4\tfrac{x^{3/4} \cdot x^{-1/4}}{x^{-6/4}}, (b) y4/3yy2/3\tfrac{y^{4/3} \cdot y}{y^{-2/3}}.

Use the Product Property in the numerator (add the exponents), then the Quotient Property (subtract the exponents):

(a)x3/4x1/4x6/4=x2/4x6/4=x2/4(6/4)=x8/4=x2(b)y4/3yy2/3=y7/3y2/3=y7/3(2/3)=y9/3=y3 \begin{array}{lrcl} \text{(a)} & \tfrac{x^{3/4} \cdot x^{-1/4}}{x^{-6/4}} &=& \tfrac{x^{2/4}}{x^{-6/4}} = x^{2/4 - (-6/4)} = x^{8/4} = x^2 \\[10pt] \text{(b)} & \tfrac{y^{4/3} \cdot y}{y^{-2/3}} &=& \tfrac{y^{7/3}}{y^{-2/3}} = y^{7/3 - (-2/3)} = y^{9/3} = y^3 \end{array}

Simplify: m2/3m1/3m5/3\tfrac{m^{2/3} \cdot m^{-1/3}}{m^{-5/3}}. Write the answer with a whole-number exponent.

Key terms

rational exponent — an exponent that is a fraction; a1/n=ana^{1/n} = \sqrt[n]{a} and am/n=(an)m=amna^{m/n} = \left(\sqrt[n]{a}\right)^m = \sqrt[n]{a^m}, connecting exponent notation to radical notation. negative rational exponent — a negative fractional exponent, rewritten with a positive exponent using am/n=1am/na^{-m/n} = \tfrac{1}{a^{m/n}}.


This section is adapted from Elementary Algebra 2e, 9.8 Rational Exponents by Lynn Marecek, MaryAnne Anthony-Smith, and Andrea Honeycutt Mathis, © OpenStax, licensed under CC BY-NC-SA 4.0. Access the original for free at openstax.org. Changes: recast the worked-example step tables as typeset math, condensed the multi-part “Try It” problems into single-part interactive exercises with instant feedback, and omitted the Be Prepared quiz, media links, Self Check, and end-of-section exercises.