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Solve Equations Using Integers; The Division Property of Equality

Solve Equations Using Integers; The Division Property of Equality

By the end of this section, you will be able to:

  • Determine whether an integer is a solution of an equation
  • Solve equations with integers using the Addition and Subtraction Properties of Equality
  • Model the Division Property of Equality
  • Solve equations using the Division Property of Equality
  • Translate word sentences to equations and solve

Determine whether a number is a solution of an equation

A solution of an equation is a value of the variable that makes a true statement when substituted into the equation. Now that we’ve worked with integers, we can find integer solutions to equations. The steps are the same whether the solution turns out to be a whole number or an integer.

Determine whether a number is a solution to an equation.

  1. Substitute the number for the variable in the equation.
  2. Simplify the expressions on both sides of the equation.
  3. Determine whether the resulting equation is true. If it is true, the number is a solution. If it is not true, the number is not a solution.

Example. Determine whether each of the following is a solution of 2x5=132x - 5 = -13: (a) x=4x=4, (b) x=4x=-4, (c) x=9x=-9.

(a) Substitute 44 for xx: 2(4)5=85=3132(4)-5 = 8-5 = 3 \ne -13. Since x=4x=4 does not result in a true equation, 44 is not a solution. (b) Substitute 4-4 for xx: 2(4)5=85=132(-4)-5 = -8-5 = -13. Since this is true, 4-4 is a solution. (c) Substitute 9-9 for xx: 2(9)5=185=23132(-9)-5 = -18-5 = -23 \ne -13. Since this is not true, 9-9 is not a solution.

Substitutex=3x = -3into the left side of2x8=142x - 8 = -14and simplify. What value do you get?

Solve equations with integers using the Addition and Subtraction Properties of Equality

We can use the same properties of equality we used with whole numbers to solve equations with integers: when you add or subtract the same quantity from both sides of an equation, you still have equality.

Properties of equality. For any numbers aa, bb, cc: Subtraction Property of Equality — if a=ba=b then ac=bca-c = b-c. Addition Property of Equality — if a=ba=b then a+c=b+ca+c = b+c.

Example. Solve y+9=5y + 9 = 5. Subtract 99 from each side to undo the addition: y+99=59y+9-9 = 5-9. Simplify: y=4y = -4. Check by substituting 4-4 into the original equation: 4+9=5-4+9 = 5, and 5=55=5 ✓.

Solve:y+11=7y + 11 = 7

Example. Solve a6=8a - 6 = -8. Add 66 to each side to undo the subtraction: a6+6=8+6a-6+6 = -8+6. Simplify: a=2a = -2. Check: 26=8-2-6 = -8 ✓.

Solve:a2=8a - 2 = -8

Model the Division Property of Equality

All of the equations solved so far have had the form x+a=bx+a=b or xa=bx-a=b, where isolating the variable meant adding or subtracting a constant. Now let’s see how to solve equations that involve multiplication — where the variable is multiplied by a number.

Picture two identical envelopes, each containing the same unknown number of counters, sitting next to 66 loose counters — the left side of the scale must equal the right side, but the counters in the envelopes are “hidden.” To find how many are in each envelope, separate the 66 counters into 22 equal groups: 6÷2=36 \div 2 = 3 counters in each envelope.

2x=6

The equation modeling this is 2x=62x = 6. We divide both sides of the equation by 22, the same way we split the counters into groups:

2x2=62x=3\frac{2x}{2} = \frac{6}{2} \qquad x = 3

Does this check? 23=62 \cdot 3 = 6 ✓ — three counters in each of two envelopes does equal six.

A second example: three identical envelopes balanced against 1212 counters models 3x=123x=12. Separating the 1212 counters into 33 groups gives 44 counters per envelope, since 12÷3=412 \div 3 = 4:

3x3=123x=4\frac{3x}{3} = \frac{12}{3} \qquad x = 4

Check: 34=123 \cdot 4 = 12 ✓.

Four identical envelopes are balanced against88loose counters. Write the equation this models (usingxxfor the unknown count per envelope), then solve forxx. Enter the value ofxx.

Solve equations using the Division Property of Equality

These examples lead to the Division Property of Equality: when you divide both sides of an equation by any nonzero number, you still have equality.

Division Property of Equality. For any numbers aa, bb, cc, with c0c \ne 0: if a=ba=b then ac=bc\tfrac{a}{c} = \tfrac{b}{c}.

Example. Solve 7x=497x = -49. To isolate xx, undo the multiplication by dividing each side by 77: 7x7=497\tfrac{7x}{7} = \tfrac{-49}{7}. Simplify: x=7x=-7. Check: 7(7)=497(-7) = -49 ✓.

Solve:8a=568a = 56

Example. Solve 3y=63-3y = 63. Divide each side by 3-3: 3y3=633\tfrac{-3y}{-3} = \tfrac{63}{-3}. Simplify: y=21y=-21. Check: 3(21)=63-3(-21) = 63 ✓.

Solve:8p=96-8p = 96

Translate word sentences to equations and solve

Now we’ll translate word sentences into equations with a variable, then solve them.

Example. Translate and solve: five more than xx is equal to 3-3. Translate: x+5=3x+5=-3. Subtract 55 from both sides: x+55=35x+5-5 = -3-5. Simplify: x=8x=-8. Check: 8+5=3-8+5 = -3 ✓.

Translate and solve: seven more thanxxis equal to2-2.

Example. Translate and solve: the difference of nn and 66 is 10-10. Translate: n6=10n-6=-10. Add 66 to each side: n6+6=10+6n-6+6 = -10+6. Simplify: n=4n=-4. Check: 46=10-4-6=-10 ✓.

Translate and solve: the difference ofppand22is4-4.

Example. Translate and solve: the number 108108 is the product of 9-9 and yy. Translate: 108=9y108 = -9y. Divide by 9-9: 1089=9y9\tfrac{108}{-9} = \tfrac{-9y}{-9}. Simplify: 12=y-12=y. Check: 108=9(12)108 = -9(-12) ✓.

Translate and solve: the number132132is the product of12-12andyy.

Key terms

solution — a value of a variable that makes an equation’s statement true. Subtraction/Addition Property of Equality — adding or subtracting the same quantity from both sides of an equation preserves equality. Division Property of Equality — dividing both sides of an equation by the same nonzero number preserves equality.

Practice

Determine whether an integer is a solution of an equation

Isx=2x = -2a solution of4x2=64x - 2 = 6?

Isx=1x = -1a solution of4x2=64x - 2 = 6?

Isx=2x = 2a solution of4x2=64x - 2 = 6?

Isa=6a = 6a solution of9a+27=639a + 27 = -63?

Isa=6a = -6a solution of9a+27=639a + 27 = -63?

Isa=10a = -10a solution of9a+27=639a + 27 = -63?

Solve equations with integers using the Addition and Subtraction Properties of Equality

Solve:n+12=5n + 12 = 5

Solve:u3=7u - 3 = -7

Solve:x+(2)=18x + (-2) = -18

Solve:r(5)=9r - (-5) = -9

Model the Division Property of Equality

envelopescounters

Write the equation modeled by the envelopes and counters above, usingxxfor the number of counters in one envelope, then solve it. Enter the value ofxx.

envelopescounters

Write the equation modeled by the envelopes and counters above, usingxxfor the number of counters in one envelope, then solve it. Enter the value ofxx.

A package of 51 cookies has33equal rows of cookies. Find the number of cookies in each row,cc, by solving the equation3c=513c = 51.

Solve equations using the Division Property of Equality

Solve:7c=56-7c = 56

Solve:120=10q-120 = 10q

Solve:24x=48024x = 480

Solve:3z=0-3z = 0

Translate word sentences to equations and solve

Translate and solve: the sum of eight andppis3-3.

Translate and solve: the product of15-15andffis7575.

Translate and solve:6-6plusccis equal to44.

Translate and solve: nine less thanmmis4-4.


This section is adapted from Prealgebra 2e, Section 3.5: Solve Equations Using Integers; The Division Property of Equality by Lynn Marecek, MaryAnne Anthony-Smith, and Andrea Honeycutt Mathis, © OpenStax, licensed under CC BY-NC-SA 4.0. Access the original for free at openstax.org. Changes: recreated the envelopes-and-counters models as accessible inline graphics; condensed prose; omitted the Be Prepared quiz, Manipulative Mathematics callout, and media links; converted the practice problems (“Try Its”) into interactive exercises with instant feedback; and adapted selected end-of-section exercises into the interactive Practice block, with each multipart exercise expanded into one question per part.