Skip to content
Simplify and Use Square Roots

Simplify and Use Square Roots

By the end of this section, you will be able to: simplify expressions with square roots, estimate square roots, approximate square roots with a calculator, simplify variable expressions with square roots, and use square roots in applications.

Simplify expressions with square roots

To start this section, we need to review some important vocabulary and notation. Remember that when a number nn is multiplied by itself, we can write this as n2n^2, which we read aloud as “nn squared.” For example, 828^2 is read as “88 squared.” We call 6464 the square of 88 because 82=648^2 = 64. Similarly, 121121 is the square of 1111, because 112=12111^2 = 121.

Square of a number. If n2=mn^2 = m, then mm is the square of nn.

Modeling squares

Do you know why we use the word square? If we construct a square with three tiles on each side, the total number of tiles would be nine. This is why we say that the square of three is nine:

32=93^2 = 9

The number 99 is called a perfect square because it is the square of a whole number. Here are the squares of the counting numbers 11 through 1515:

nn112233445566778899101011111212131314141515
n2n^2114499161625253636494964648181100100121121144144169169196196225225
Perfect squares. A perfect square is the square of a whole number.

What happens when you square a negative number?

(8)2=(8)(8)=64(-8)^2 = (-8)(-8) = 64

When we multiply two negative numbers, the product is always positive. So, the square of a negative number is always positive. In fact, the squares of the negative integers from 1-1 to 15-15 are exactly the same as the squares of the positive integers from 11 to 1515 shown in the table above.

Square roots

Sometimes we will need to look at the relationship between numbers and their squares in reverse. Because 102=10010^2 = 100, we say 100100 is the square of 1010. We can also say that 1010 is a square root of 100100.

Square root of a number. A number whose square is mm is called a square root of mm. If n2=mn^2 = m, then nn is a square root of mm.

Notice (10)2=100(-10)^2 = 100 also, so 10-10 is also a square root of 100100. Therefore, both 1010 and 10-10 are square roots of 100100. So, every positive number has two square roots: one positive and one negative.

What if we only want the positive square root of a positive number? The radical sign, x\sqrt{\phantom{x}}, stands for the positive square root. The positive square root is also called the principal square root.

Square root notation. m\sqrt{m} is read as “the square root of mm.” If m=n2m = n^2, then m=n\sqrt{m} = n for n0n \geq 0. The number under the radical sign is called the radicand.

We can also use the radical sign for the square root of zero. Because 02=00^2 = 0, 0=0\sqrt{0} = 0. Notice that zero has only one square root. The chart below shows the square roots of the first 1515 perfect square numbers:

Perfect square114499161625253636494964648181100100121121144144169169196196225225
Square root112233445566778899101011111212131314141515

Example. Simplify: (a) 25\sqrt{25} (b) 121\sqrt{121}.

(a) Since 52=255^2 = 25: 25=5\sqrt{25} = 5.

(b) Since 112=12111^2 = 121: 121=11\sqrt{121} = 11.

Simplify: 36\sqrt{36}

Simplify: 169\sqrt{169}

Every positive number has two square roots, and the radical sign indicates the positive one. We write 100=10\sqrt{100} = 10. If we want to find the negative square root of a number, we place a negative in front of the radical sign. For example, 100=10-\sqrt{100} = -10.

Example. Simplify: (a) 9-\sqrt{9} (b) 144-\sqrt{144}.

(a) The negative is in front of the radical sign: 9=3-\sqrt{9} = -3.

(b) The negative is in front of the radical sign: 144=12-\sqrt{144} = -12.

Simplify: 4-\sqrt{4}

Simplify: 225-\sqrt{225}

Square root of a negative number

Can we simplify 25\sqrt{-25}? Is there a number whose square is 25-25? None of the numbers that we have dealt with so far have a square that is 25-25. Why? Any positive number squared is positive, and any negative number squared is also positive. So we say there is no real number equal to 25\sqrt{-25}. If we are asked to find the square root of any negative number, we say that the solution is not a real number.

Example. Simplify: (a) 169\sqrt{-169} (b) 121-\sqrt{121}.

(a) There is no real number whose square is 169-169. Therefore, 169\sqrt{-169} is not a real number.

(b) The negative is in front of the radical sign, so we find the opposite of the square root of 121121: 121=11-\sqrt{121} = -11.

Is there a real number whose square is 49-49 (in other words, is 49\sqrt{-49} a real number)? Enter 1 for yes or 0 for no.

Simplify: 121-\sqrt{121}

Square roots and the order of operations

When using the order of operations to simplify an expression that has square roots, we treat the radical sign as a grouping symbol. We simplify any expressions under the radical sign before performing other operations.

Example. Simplify: (a) 25+144\sqrt{25} + \sqrt{144} (b) 25+144\sqrt{25 + 144}.

(a) Simplify each radical first, then add: 5+12=175 + 12 = 17.

(b) Add under the radical sign first, then simplify: 169=13\sqrt{169} = 13.

Notice the different answers in (a) and (b) — it is important to follow the order of operations correctly.

Simplify: 9+16\sqrt{9} + \sqrt{16}

Simplify: 9+16\sqrt{9 + 16}

Estimate square roots

So far we have only worked with square roots of perfect squares. The square roots of other numbers are not whole numbers. We might conclude that the square roots of numbers between 44 and 99 will be between 22 and 33, and they will not be whole numbers. Based on this pattern, we could say that 5\sqrt{5} is between 22 and 33. Using inequality symbols, we write 2<5<32 < \sqrt{5} < 3.

Example. Estimate 60\sqrt{60} between two consecutive whole numbers.

Think of the perfect squares closest to 6060: 49<60<6449 < 60 < 64. Since 6060 is between the perfect squares 4949 and 6464, 60\sqrt{60} is between their square roots: 7<60<87 < \sqrt{60} < 8.

Estimate 38\sqrt{38} between two consecutive whole numbers. Enter the smaller of the two.

Estimate 84\sqrt{84} between two consecutive whole numbers. Enter the smaller of the two.

Approximate square roots with a calculator

There are mathematical methods to approximate square roots, but it is much more convenient to use a calculator to find square roots. When you use your calculator to find the square root of a number that is not a perfect square, the answer that you see is not the exact number. It is an approximation, to the number of digits shown on your calculator’s display. The symbol for an approximation is \approx and it is read approximately.

Suppose your calculator has a 1010-digit display. Using it to find the square root of 55 will give 2.2360679772.236067977. This is the approximate square root of 55. When we report the answer, we should use the “approximately equal to” sign instead of an equal sign: 52.236067978\sqrt{5} \approx 2.236067978.

You will seldom use this many digits for applications in algebra. So, if you wanted to round 5\sqrt{5} to two decimal places, you would write 52.24\sqrt{5} \approx 2.24.

How do we know these values are approximations and not the exact values? Look at what happens when we square them: 2.2360679782=5.0000000022.236067978^2 = 5.000000002 and 2.242=5.01762.24^2 = 5.0176. The squares are close, but not exactly equal, to 55.

Example. Round 17\sqrt{17} to two decimal places using a calculator.

Use the calculator square root key: 4.1231056264.123105626. Round to two decimal places: 174.12\sqrt{17} \approx 4.12.

Round 11\sqrt{11} to two decimal places.

Round 13\sqrt{13} to two decimal places.

Simplify variable expressions with square roots

Expressions with square roots that we have looked at so far have not had any variables. What happens when we have to find a square root of a variable expression?

Consider 9x2\sqrt{9x^2}, where x0x \geq 0. Can you think of an expression whose square is 9x29x^2? (3x)2=9x2(3x)^2 = 9x^2, so 9x2=3x\sqrt{9x^2} = 3x.

When we use a variable in a square root expression, for our work, we will assume that the variable represents a non-negative number. In every example and exercise that follows, each variable in a square root expression is greater than or equal to zero.

Example. Simplify: x2\sqrt{x^2}.

Think about what we would have to square to get x2x^2: since (x)2=x2(x)^2 = x^2, x2=x\sqrt{x^2} = x.

Simplify: y2\sqrt{y^2}

Simplify: m2\sqrt{m^2}

Example. Simplify: 16x2\sqrt{16x^2}.

Since (4x)2=16x2(4x)^2 = 16x^2: 16x2=4x\sqrt{16x^2} = 4x.

Simplify: 64x2\sqrt{64x^2}

Simplify: 169y2\sqrt{169y^2}

Example. Simplify: 81y2-\sqrt{81y^2}.

Since (9y)2=81y2(9y)^2 = 81y^2: 81y2=9y-\sqrt{81y^2} = -9y.

Simplify: 121y2-\sqrt{121y^2}

Simplify: 100p2-\sqrt{100p^2}

Example. Simplify: 36x2y2\sqrt{36x^2y^2}.

Since (6xy)2=36x2y2(6xy)^2 = 36x^2y^2: 36x2y2=6xy\sqrt{36x^2y^2} = 6xy.

Simplify: 100a2b2\sqrt{100a^2b^2}

Simplify: 225m2n2\sqrt{225m^2n^2}

Use square roots in applications

As you progress through your college courses, you’ll encounter several applications of square roots. Once again, if we use our strategy for applications, it will give us a plan for finding the answer.

Use a strategy for applications with square roots.

  1. Identify what you are asked to find.
  2. Write a phrase that gives the information to find it.
  3. Translate the phrase to an expression.
  4. Simplify the expression.
  5. Write a complete sentence that answers the question.

Square roots and area

We have solved applications with area before. If we were given the length of the sides of a square, we could find its area by squaring the length of its sides. Now we can find the length of the sides of a square if we are given the area, by finding the square root of the area.

If the area of the square is AA square units, the length of a side is A\sqrt{A} units. For example, if the area is 99 square units, the side is 9=3\sqrt{9} = 3 units; if the area is 144144 square units, the side is 144=12\sqrt{144} = 12 units.

Example. Mike and Lychelle want to make a square patio. They have enough concrete for an area of 200200 square feet. To the nearest tenth of a foot, how long can a side of their square patio be?

We know the area of the square is 200200 square feet and want to find the length of the side. Translate to an expression: A\sqrt{A}. Evaluate A\sqrt{A} when A=200A = 200: 200\sqrt{200}. Use your calculator: 14.14213514.142135\ldots. Round to one decimal place: 14.114.1 feet. Each side of the patio should be 14.114.1 feet.

Katie wants to plant a square lawn in her front yard. She has enough sod to cover an area of 370 square feet. To the nearest tenth of a foot, how long can a side of her square lawn be?

Sergio wants to make a square mosaic as an inlay for a table he is building. He has enough tile to cover an area of 2704 square centimeters. How long can a side of his mosaic be?

Square roots and gravity

Another application of square roots involves gravity. On Earth, if an object is dropped from a height of hh feet, the time in seconds it will take to reach the ground is found by evaluating the expression h4\tfrac{\sqrt{h}}{4}. For example, if an object is dropped from a height of 6464 feet, we can find the time it takes to reach the ground by evaluating 644=84=2\tfrac{\sqrt{64}}{4} = \tfrac{8}{4} = 2. It would take 22 seconds for an object dropped from a height of 6464 feet to reach the ground.

Example. Christy dropped her sunglasses from a bridge 400400 feet above a river. How many seconds does it take for the sunglasses to reach the river?

Translate to an expression: h4\tfrac{\sqrt{h}}{4}. Evaluate h4\tfrac{\sqrt{h}}{4} when h=400h = 400: 4004\tfrac{\sqrt{400}}{4}. Find the square root of 400400: 204\tfrac{20}{4}. Simplify: 55. It will take 55 seconds for the sunglasses to reach the river.

A helicopter drops a rescue package from a height of 1296 feet. How many seconds does it take for the package to reach the ground?

A window washer drops a squeegee from a platform 196 feet above the sidewalk. How many seconds does it take for the squeegee to reach the sidewalk?

Square roots and accident investigations

Police officers investigating car accidents measure the length of the skid marks on the pavement. Then they use square roots to determine the speed, in miles per hour, a car was going before applying the brakes. According to some formulas, if the length of the skid marks is dd feet, then the speed of the car can be found by evaluating 24d\sqrt{24d}.

Example. After a car accident, the skid marks for one car measured 190190 feet. To the nearest tenth, what was the speed of the car (in mph) before the brakes were applied?

Translate to an expression: 24d\sqrt{24d}. Evaluate 24d\sqrt{24d} when d=190d = 190: 24190=4,560\sqrt{24 \cdot 190} = \sqrt{4{,}560}. Use your calculator: 67.52777267.527772\ldots. Round to tenths: 67.567.5. The speed of the car was approximately 67.567.5 miles per hour.

An accident investigator measured the skid marks of a car and found their length was 76 feet. To the nearest tenth, what was the speed of the car before the brakes were applied?

The skid marks of a vehicle involved in an accident were 122 feet long. To the nearest tenth, how fast had the vehicle been going before the brakes were applied?

Key terms

perfect square — the square of a whole number. square root — a number whose square is mm; if n2=mn^2 = m, then nn is a square root of mm. radical sign — the symbol x\sqrt{\phantom{x}}, which denotes the principal (positive) square root. radicand — the number or expression under a radical sign. principal square root — the positive square root of a positive number.


This section is adapted from Prealgebra 2e, Section 5.7: Simplify and Use Square Roots by Lynn Marecek, MaryAnne Anthony-Smith, and Andrea Honeycutt Mathis, © OpenStax, licensed under CC BY-NC-SA 4.0. Access the original for free at openstax.org. Changes: recreated the perfect-square and square-root charts, the area/side-length table, and the tile-diagram concept as markdown tables and prose; omitted the Be Prepared quiz, Manipulative Mathematics and Links to Literacy callouts, Media links, and end-of-section exercises; and converted the practice problems (“Try Its”) into interactive exercises with instant feedback.