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Solve Equations Using the Division and Multiplication Properties of Equality

Solve Equations Using the Division and Multiplication Properties of Equality

By the end of this section, you will be able to: solve equations using the Division and Multiplication Properties of Equality, and solve equations that need to be simplified.

Solve equations using the Division and Multiplication Properties of Equality

We introduced the Multiplication and Division Properties of Equality earlier, modeling how these properties worked using envelopes and counters and then applying them to solving equations. We restate them again here as we prepare to use these properties again.

Division and Multiplication Properties of Equality.

Division Property of Equality: for all real numbers aa, bb, cc, and c0c \neq 0, if a=ba = b, then ac=bc\tfrac{a}{c} = \tfrac{b}{c}.

Multiplication Property of Equality: for all real numbers aa, bb, cc, if a=ba = b, then ac=bcac = bc.

When you divide or multiply both sides of an equation by the same quantity, you still have equality. Let’s review how these properties of equality can be applied in order to solve equations. Remember, the goal is to “undo” the operation on the variable. In the example below the variable is multiplied by 44, so we will divide both sides by 44 to “undo” the multiplication.

Example. Solve: 4x=284x = -28.

Use the Division Property of Equality to divide both sides by 44:

4x4=284\tfrac{4x}{4} = \tfrac{-28}{4}

Simplify:

x=7x = -7

Check: substitute x=7x = -7 into 4x=284x = -28:

4(7)=?2828=284(-7) \stackrel{?}{=} -28 \qquad -28 = -28 \checkmark

Since this is a true statement, x=7x = -7 is a solution to 4x=284x = -28.

Solve: 3y=483y = -48.

In that example, to “undo” multiplication, we divided. When the variable is divided by a number, we “undo” division by multiplying.

Example. Solve: a7=42\tfrac{a}{-7} = -42.

Here aa is divided by 7-7. We can multiply both sides by 7-7 to isolate aa:

7(a7)=7(42)7a7=294-7\left(\tfrac{a}{-7}\right) = -7(-42) \qquad\qquad \tfrac{-7a}{-7} = 294

Simplify:

a=294a = 294

Check: substitute a=294a = 294 into a7=42\tfrac{a}{-7} = -42:

2947=?4242=42\tfrac{294}{-7} \stackrel{?}{=} -42 \qquad -42 = -42 \checkmark

The solution checks.

Solve: b6=24\tfrac{b}{-6} = -24.

Example. Solve: r=2-r = 2.

Remember r-r is equivalent to 1r-1r. Rewrite r-r as 1r-1r, then divide both sides by 1-1:

1r=21r1=21-1r = 2 \qquad\qquad \tfrac{-1r}{-1} = \tfrac{2}{-1}r=2r = -2

Check: substitute r=2r = -2 into r=2-r = 2:

(2)=?22=2-(-2) \stackrel{?}{=} 2 \qquad 2 = 2 \checkmark

We saw earlier that there are two other ways to solve r=2-r = 2: we could multiply both sides by 1-1, or we could take the opposite of both sides. All three approaches lead to the same solution.

Solve: k=8-k = 8.

Example. Solve: 23x=18\tfrac{2}{3}x = 18.

Since the product of a number and its reciprocal is 11, our strategy will be to isolate xx by multiplying by the reciprocal of 23\tfrac{2}{3}. Multiply both sides by 32\tfrac{3}{2}, the reciprocal of 23\tfrac{2}{3}:

3223x=3218\tfrac{3}{2} \cdot \tfrac{2}{3}x = \tfrac{3}{2} \cdot 18

Reciprocals multiply to one, so the left side becomes 1x1x:

1x=321811x = \tfrac{3}{2} \cdot \tfrac{18}{1}

Multiply:

x=27x = 27

Check: substitute x=27x = 27 into 23x=18\tfrac{2}{3}x = 18:

2327=?1818=18\tfrac{2}{3} \cdot 27 \stackrel{?}{=} 18 \qquad 18 = 18 \checkmark

Notice that we could have divided both sides of the equation 23x=18\tfrac{2}{3}x = 18 by 23\tfrac{2}{3} to isolate xx. While this would work, multiplying by the reciprocal requires fewer steps.

Solve: 25n=14\tfrac{2}{5}n = 14.

Solve equations that need to be simplified

Many equations start out more complicated than the ones we’ve just solved. First, we need to simplify both sides of the equation as much as possible.

Example. Solve: 8x+9x5x=3+158x + 9x - 5x = -3 + 15.

Start by combining like terms to simplify each side:

8x+9x5x=3+1512x=128x + 9x - 5x = -3 + 15 \quad\longrightarrow\quad 12x = 12

Divide both sides by 1212 to isolate xx:

12x12=1212x=1\tfrac{12x}{12} = \tfrac{12}{12} \qquad\qquad x = 1

Check: substitute x=1x = 1 into the original equation:

8(1)+9(1)5(1)=?3+158+95=?1212=128(1) + 9(1) - 5(1) \stackrel{?}{=} -3 + 15 \qquad 8 + 9 - 5 \stackrel{?}{=} 12 \qquad 12 = 12 \checkmark

The solution checks.

Solve: 7x+6x4x=8+267x + 6x - 4x = -8 + 26.

Sometimes the variable ends up on the right side of the equation after combining like terms.

Example. Solve: 1120=17y8y6y11 - 20 = 17y - 8y - 6y.

Simplify each side by combining like terms:

1120=17y8y6y9=3y11 - 20 = 17y - 8y - 6y \quad\longrightarrow\quad -9 = 3y

Divide both sides by 33 to isolate yy:

93=3y33=y\tfrac{-9}{3} = \tfrac{3y}{3} \qquad\qquad -3 = y

Check: substitute y=3y = -3 into the original equation:

1120=?17(3)8(3)6(3)11 - 20 \stackrel{?}{=} 17(-3) - 8(-3) - 6(-3)1120=?51+24+189=911 - 20 \stackrel{?}{=} -51 + 24 + 18 \qquad -9 = -9 \checkmark

Notice that the variable ended up on the right side of the equal sign when we solved the equation. You may prefer to take one more step to write the solution with the variable on the left side.

Solve: 1827=15c9c3c18 - 27 = 15c - 9c - 3c.

Some equations have parentheses that must be distributed before we can combine like terms.

Example. Solve: 3(n2)6=21-3(n - 2) - 6 = 21.

Remember — always simplify each side first. Distribute, then combine like terms:

3(n2)6=213n+66=213n=21-3(n - 2) - 6 = 21 \quad\longrightarrow\quad -3n + 6 - 6 = 21 \quad\longrightarrow\quad -3n = 21

Divide both sides by 3-3 to isolate nn:

3n3=213n=7\tfrac{-3n}{-3} = \tfrac{21}{-3} \qquad\qquad n = -7

Check: substitute n=7n = -7 into the original equation:

3(72)6=?213(9)6=?21276=?2121=21-3(-7 - 2) - 6 \stackrel{?}{=} 21 \qquad -3(-9) - 6 \stackrel{?}{=} 21 \qquad 27 - 6 \stackrel{?}{=} 21 \qquad 21 = 21 \checkmark

The solution checks.

Solve: 4(n2)8=24-4(n - 2) - 8 = 24.

Solve: 6(n2)12=30-6(n - 2) - 12 = 30.

Key terms

Division Property of Equality — for all real numbers aa, bb, cc, and c0c \neq 0, if a=ba = b, then ac=bc\tfrac{a}{c} = \tfrac{b}{c}. Multiplication Property of Equality — for all real numbers aa, bb, and cc, if a=ba = b, then ac=bcac = bc.


This section is adapted from Prealgebra 2e, Section 8.2: Solve Equations Using the Division and Multiplication Properties of Equality by Lynn Marecek, MaryAnne Anthony-Smith, and Andrea Honeycutt Mathis, © OpenStax, licensed under CC BY-NC-SA 4.0. Access the original for free at openstax.org. Changes: omitted the Be Prepared quiz, Links to Literacy and media links, and end-of-section exercises; and converted the practice problems (“Try Its”) into interactive exercises with instant feedback.