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Use Properties of Angles, Triangles, and the Pythagorean Theorem

Use Properties of Angles, Triangles, and the Pythagorean Theorem

By the end of this section, you will be able to: use the properties of angles, use the properties of triangles, and use the Pythagorean Theorem.

So far in this chapter we have focused on solving word problems. In this section, we apply our problem-solving strategy to some common geometry problems.

Use the properties of angles

Are you familiar with the phrase “do a 180180”? It means to turn so that you face the opposite direction — it comes from the fact that the measure of an angle that makes a straight line is 180180 degrees.

180°

An angle is formed by two rays that share a common endpoint. Each ray is called a side of the angle, and the common endpoint is called the vertex. An angle is named by its vertex — in the figure below, A\angle A is the angle with vertex at point AA. The measure of A\angle A is written mAm\angle A.

A

We measure angles in degrees, using the symbol ° to represent degrees, and the abbreviation mm for the measure of an angle. So if A\angle A is 2727^\circ, we write mA=27m\angle A = 27.

If the sum of the measures of two angles is 180180^\circ, the angles are called supplementary angles — each angle is the supplement of the other. If the sum of the measures of two angles is 9090^\circ, the angles are called complementary angles — each angle is the complement of the other.

Supplementary and complementary angles. If the sum of the measures of two angles is 180180^\circ, the angles are supplementary. If A\angle A and B\angle B are supplementary, then mA+mB=180m\angle A + m\angle B = 180^\circ.

If the sum of the measures of two angles is 9090^\circ, the angles are complementary. If A\angle A and B\angle B are complementary, then mA+mB=90m\angle A + m\angle B = 90^\circ.

In this section and the next, geometry formulas will name the variables and give us the equation to solve. Since these applications all involve geometric shapes, it will also help to draw a figure and label it with the information from the problem.

Use a problem-solving strategy for geometry applications.

  1. Read the problem and make sure you understand all the words and ideas. Draw a figure and label it with the given information.
  2. Identify what you are looking for.
  3. Name what you are looking for and choose a variable to represent it.
  4. Translate into an equation by writing the appropriate formula or model for the situation. Substitute in the given information.
  5. Solve the equation using good algebra techniques.
  6. Check the answer in the problem and make sure it makes sense.
  7. Answer the question with a complete sentence.

Example. An angle measures 4040^\circ. Find (a) its supplement, and (b) its complement.

(a) Let s=s = the measure of the supplement. Since supplementary angles sum to 180180^\circ: s+40=180s + 40 = 180, so s=140s = 140. Checking: 140+40=180140 + 40 = 180. The supplement of the 4040^\circ angle is 140140^\circ.

(b) Let c=c = the measure of the complement. Since complementary angles sum to 9090^\circ: c+40=90c + 40 = 90, so c=50c = 50. Checking: 50+40=9050 + 40 = 90. The complement of the 4040^\circ angle is 5050^\circ.

An angle measures 2525^\circ. Find its supplement.

An angle measures 7777^\circ. Find its complement.

Did you notice that the words complementary and supplementary are in alphabetical order just like 9090 and 180180 are in numerical order?

Example. Two angles are supplementary. The larger angle is 3030^\circ more than the smaller angle. Find the measure of both angles.

Let a=a = measure of the smaller angle, so a+30=a + 30 = measure of the larger angle. Since the angles are supplementary:

(a+30)+a=180(a + 30) + a = 180

Combining like terms: 2a+30=1802a + 30 = 180, so 2a=1502a = 150 and a=75a = 75 (the smaller angle). The larger angle is a+30=105a + 30 = 105. Checking: 75+105=18075 + 105 = 180. The measures of the angles are 7575^\circ and 105105^\circ.

Two angles are supplementary. The larger angle is 100100^\circ more than the smaller angle. Find the measure of the smaller angle.

Two angles are complementary. The larger angle is 4040^\circ more than the smaller angle. Find the measure of the smaller angle.

Use the properties of triangles

Triangles have three sides and three angles, and are named by their vertices. The triangle below is called ΔABC\Delta ABC, read “triangle ABC.” Each side is labeled with a lowercase letter to match the uppercase letter of the opposite vertex.

ACBbac

The three angles of a triangle are related in a special way: the sum of their measures is 180180^\circ.

Sum of the measures of the angles of a triangle. For any ΔABC\Delta ABC, the sum of the measures of the angles is 180180^\circ:

mA+mB+mC=180m\angle A + m\angle B + m\angle C = 180^\circ

Example. The measures of two angles of a triangle are 5555^\circ and 8282^\circ. Find the measure of the third angle.

Let x=x = the measure of the third angle. Substituting into the angle-sum formula:

55+82+x=180137+x=180x=43 55 + 82 + x = 180 \qquad\Rightarrow\qquad 137 + x = 180 \qquad\Rightarrow\qquad x = 43

Checking: 55+82+43=18055 + 82 + 43 = 180. The measure of the third angle is 4343 degrees.

The measures of two angles of a triangle are 3131^\circ and 128128^\circ. Find the measure of the third angle.

A triangle has angles of 4949^\circ and 7575^\circ. Find the measure of the third angle.

Right triangles

A right triangle has one 9090^\circ angle, often marked with a small square in the corner.

90°

If we know a triangle is a right triangle, one angle measures 9090^\circ, so we only need the measure of one of the other angles to find the third.

Example. One angle of a right triangle measures 2828^\circ. What is the measure of the third angle?

Let x=x = the measure of the third angle:

x+90+28=180x+118=180x=62 x + 90 + 28 = 180 \qquad\Rightarrow\qquad x + 118 = 180 \qquad\Rightarrow\qquad x = 62

Checking: 90+28+62=18090 + 28 + 62 = 180. The measure of the third angle is 6262^\circ.

One angle of a right triangle measures 5656^\circ. What is the measure of the other angle?

One angle of a right triangle measures 4545^\circ. What is the measure of the other angle?

When one angle is defined in terms of another, it helps to write expressions for all the angles before drawing the figure.

Example. The measure of one angle of a right triangle is 2020^\circ more than the measure of the smallest angle. Find the measures of all three angles.

Let a=a = the first (smallest) angle, so a+20=a + 20 = the second angle, and 90=90 = the third angle (the right angle). Substituting into the angle-sum formula:

a+(a+20)+90=1802a+110=180a + (a + 20) + 90 = 180 \qquad\Rightarrow\qquad 2a + 110 = 1802a=70a=35 (first angle)2a = 70 \qquad\Rightarrow\qquad a = 35 \text{ (first angle)}

The second angle is a+20=55a + 20 = 55, and the third angle is 9090. Checking: 35+55+90=18035 + 55 + 90 = 180. The three angles measure 3535^\circ, 5555^\circ, and 9090^\circ.

The measure of one angle of a right triangle is 5050^\circ more than the measure of the smallest angle. Find the measure of the smallest angle.

The measure of one angle of a right triangle is 3030^\circ more than the measure of the smallest angle. Find the measure of the smallest angle.

Similar triangles

When we use a map to plan a trip, a sketch to build a bookcase, or a pattern to sew a dress, we are working with similar figures. In geometry, if two figures have exactly the same shape but different sizes, we say they are similar figures — one is a scale model of the other. The corresponding sides of the two figures have the same ratio, and all their corresponding angles have the same measures.

Properties of similar triangles. If two triangles are similar, their corresponding angle measures are equal and their corresponding side lengths are in the same ratio. For ΔABC\Delta ABC similar to ΔXYZ\Delta XYZ:

mA=mX,mB=mY,mC=mZm\angle A = m\angle X, \quad m\angle B = m\angle Y, \quad m\angle C = m\angle Zax=by=cz\frac{a}{x} = \frac{b}{y} = \frac{c}{z}

The length of a side of a triangle may also be referred to by its endpoints — two vertices of the triangle. For example, in ΔABC\Delta ABC, the length aa can also be written BCBC, the length bb can also be written ACAC, and the length cc can also be written ABAB. This notation helps match up corresponding side lengths when solving similar triangles.

Example. ΔABC\Delta ABC and ΔXYZ\Delta XYZ are similar triangles. In ΔABC\Delta ABC, side AB=4AB = 4 and side AC=3.2AC = 3.2; in ΔXYZ\Delta XYZ, the corresponding side XY=3XY = 3. Find the length of the third side of each triangle (side BC=aBC = a in ΔABC\Delta ABC, and side XZ=yXZ = y in ΔXYZ\Delta XYZ), given that side YZ=4.5YZ = 4.5.

Since the triangles are similar, corresponding sides are in the same ratio:

ABXY=BCYZ=ACXZ\frac{AB}{XY} = \frac{BC}{YZ} = \frac{AC}{XZ}

Since AB=4AB = 4 corresponds to XY=3XY = 3, we use the ratio ABXY=43\frac{AB}{XY} = \frac{4}{3} to find the other sides. To find aa:

43=a4.53a=4(4.5)3a=18a=6 \frac{4}{3} = \frac{a}{4.5} \qquad\Rightarrow\qquad 3a = 4(4.5) \qquad\Rightarrow\qquad 3a = 18 \qquad\Rightarrow\qquad a = 6

To find yy:

43=3.2y4y=3(3.2)4y=9.6y=2.4 \frac{4}{3} = \frac{3.2}{y} \qquad\Rightarrow\qquad 4y = 3(3.2) \qquad\Rightarrow\qquad 4y = 9.6 \qquad\Rightarrow\qquad y = 2.4

Checking: 4(4.5)=6(3)4(4.5) = 6(3) gives 18=1818 = 18, and 4(2.4)=3.2(3)4(2.4) = 3.2(3) gives 9.6=9.69.6 = 9.6. The third side of ΔABC\Delta ABC is 66, and the third side of ΔXYZ\Delta XYZ is 2.42.4.

Triangle ABC is similar to triangle XYZ. Side AB=17AB = 17 corresponds to side XY=25.5XY = 25.5, and side BC=aBC = a corresponds to side YZ=12YZ = 12. Find aa.

Using the same similar triangles (AB=17AB = 17 corresponds to XY=25.5XY = 25.5), side AC=15AC = 15 corresponds to side XZ=yXZ = y. Find yy.

Use the Pythagorean Theorem

The Pythagorean Theorem is a special property of right triangles that has been used since ancient times, named after the Greek philosopher and mathematician Pythagoras. In a right triangle, the side opposite the 9090^\circ angle is called the hypotenuse, and the other two sides are called the legs.

abc

The Pythagorean Theorem tells how the lengths of the three sides of a right triangle relate to each other: in any right triangle, the sum of the squares of the two legs equals the square of the hypotenuse.

The Pythagorean Theorem. In any right triangle ΔABC\Delta ABC,

a2+b2=c2a^2 + b^2 = c^2

where cc is the length of the hypotenuse and aa and bb are the lengths of the legs.

To solve for a side length, recall that if m=n2m = n^2, then m=n\sqrt{m} = n for n0n \geq 0. For example, 25\sqrt{25} is 55 because 52=255^2 = 25.

Example. Use the Pythagorean Theorem to find the length of the hypotenuse of a right triangle whose legs measure 33 and 44.

Let c=c = the length of the hypotenuse:

a2+b2=c232+42=c2a^2 + b^2 = c^2 \qquad\Rightarrow\qquad 3^2 + 4^2 = c^29+16=c225=c225=c5=c 9 + 16 = c^2 \qquad\Rightarrow\qquad 25 = c^2 \qquad\Rightarrow\qquad \sqrt{25} = c \qquad\Rightarrow\qquad 5 = c

Checking: 32+42=523^2 + 4^2 = 5^2 gives 9+16=259 + 16 = 25. The length of the hypotenuse is 55.

Use the Pythagorean Theorem to find the length of the hypotenuse of a right triangle whose legs measure 6 and 8.

Use the Pythagorean Theorem to find the length of the hypotenuse of a right triangle whose legs measure 15 and 8.

Example. Use the Pythagorean Theorem to find the length of the longer leg of a right triangle whose hypotenuse is 1313 and whose shorter leg is 55.

Let b=b = the unknown leg:

a2+b2=c252+b2=132a^2 + b^2 = c^2 \qquad\Rightarrow\qquad 5^2 + b^2 = 13^225+b2=169b2=144b=144b=12 25 + b^2 = 169 \qquad\Rightarrow\qquad b^2 = 144 \qquad\Rightarrow\qquad b = \sqrt{144} \qquad\Rightarrow\qquad b = 12

Checking: 52+122=1325^2 + 12^2 = 13^2 gives 25+144=16925 + 144 = 169. The length of the leg is 1212.

Use the Pythagorean Theorem to find the length of the leg of a right triangle whose hypotenuse is 17 and whose other leg is 15.

Use the Pythagorean Theorem to find the length of the leg of a right triangle whose hypotenuse is 15 and whose other leg is 9.

Example. Kelvin is building a gazebo and wants to brace each corner by placing a 1010-inch wooden bracket diagonally, as shown, so that the distances from the corner to each end of the bracket are equal. How far below the corner should he fasten the bracket? Approximate to the nearest tenth of an inch.

xx10 in

Let x=x = the distance from the corner along each side. Since both legs are equal:

a2+b2=c2x2+x2=102a^2 + b^2 = c^2 \qquad\Rightarrow\qquad x^2 + x^2 = 10^22x2=100x2=50x=507.1 2x^2 = 100 \qquad\Rightarrow\qquad x^2 = 50 \qquad\Rightarrow\qquad x = \sqrt{50} \approx 7.1

Checking: (7.1)2+(7.1)2102(7.1)^2 + (7.1)^2 \approx 10^2. Kelvin should fasten each piece of wood approximately 7.17.1 inches from the corner.

John puts the base of a 13-ft ladder 5 feet from the wall of his house. How far up the wall does the ladder reach?

Randy wants to attach a 17-ft string of lights to the top of the 15-ft mast of his sailboat, running down to the deck. How far from the base of the mast should he attach the end of the light string?

Key terms

angle — a figure formed by two rays sharing a common endpoint (the vertex). supplementary angles — two angles whose measures sum to 180180^\circ. complementary angles — two angles whose measures sum to 9090^\circ. right triangle — a triangle with one 9090^\circ angle. similar triangles — triangles with the same shape but not necessarily the same size, whose corresponding angles are equal and corresponding sides are proportional. hypotenuse — the side of a right triangle opposite the right angle. leg (of a right triangle) — either of the two sides that form the right angle. Pythagorean Theorem — in a right triangle, a2+b2=c2a^2 + b^2 = c^2, where cc is the hypotenuse and a,ba, b are the legs.


This section is adapted from Prealgebra 2e, Section 9.3: Use Properties of Angles, Triangles, and the Pythagorean Theorem by Lynn Marecek, MaryAnne Anthony-Smith, and Andrea Honeycutt Mathis, © OpenStax, licensed under CC BY-NC-SA 4.0. Access the original for free at openstax.org. Changes: recreated the angle, triangle, and Pythagorean Theorem figures as accessible inline graphics; omitted the Be Prepared quiz, the Media callout, the house and sailboat illustrations, and end-of-section exercises; and converted the practice problems (“Try Its”) into interactive exercises with instant feedback.