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Divide Monomials

By the end of this section, you will be able to: simplify expressions using the Quotient Property of Exponents, simplify expressions with zero exponents, simplify expressions using the Quotient to a Power Property, simplify expressions by applying several properties, and divide monomials.

Simplify expressions using the Quotient Property of Exponents

Earlier in this chapter, we developed the properties of exponents for multiplication. We summarize them here.

Summary of exponent properties for multiplication. If a,ba, b are real numbers and m,nm, n are whole numbers, then

Product Propertyaman=am+nPower Property(am)n=amnProduct to a Power(ab)m=ambm \begin{array}{ll} \text{Product Property} & a^m \cdot a^n = a^{m+n} \\[4pt] \text{Power Property} & (a^m)^n = a^{m \cdot n} \\[4pt] \text{Product to a Power} & (ab)^m = a^m b^m \end{array}

Now we will look at the exponent properties for division. A quick memory refresher may help before we get started. You have already learned that fractions may be simplified by dividing out common factors from the numerator and denominator using the Equivalent Fractions Property. This property will also help us work with algebraic fractions — which are also quotients.

Equivalent Fractions Property. If a,b,ca, b, c are whole numbers where b0,c0b \neq 0, c \neq 0, then

ab=acbcandacbc=ab\frac{a}{b} = \frac{a \cdot c}{b \cdot c} \qquad \text{and} \qquad \frac{a \cdot c}{b \cdot c} = \frac{a}{b}

As before, we’ll try to discover a property by looking at some examples. Consider x5x2\tfrac{x^5}{x^2} and x2x3\tfrac{x^2}{x^3}. Writing out the factors:

x5x2=xxxxxxx=xxx1=x3x2x3=xxxxx=1x\frac{x^5}{x^2} = \frac{x \cdot x \cdot x \cdot x \cdot x}{x \cdot x} = \frac{x \cdot x \cdot x}{1} = x^3 \qquad\qquad \frac{x^2}{x^3} = \frac{x \cdot x}{x \cdot x \cdot x} = \frac{1}{x}

Notice that in each case the bases were the same and we subtracted the exponents.

  • When the larger exponent was in the numerator, we were left with factors in the numerator and 11 in the denominator, which we simplified.
  • When the larger exponent was in the denominator, we were left with factors in the denominator, and 11 in the numerator, which could not be simplified.

So we write x5x2=x52=x3\tfrac{x^5}{x^2} = x^{5-2} = x^3 and x2x3=1x32=1x\tfrac{x^2}{x^3} = \tfrac{1}{x^{3-2}} = \tfrac{1}{x}.

Quotient Property of Exponents. If aa is a real number, a0a \neq 0, and m,nm, n are whole numbers, then

aman=amn,m>nandaman=1anm,n>m\frac{a^m}{a^n} = a^{m-n}, \quad m > n \qquad\qquad \text{and} \qquad\qquad \frac{a^m}{a^n} = \frac{1}{a^{n-m}}, \quad n > m

A couple of examples with numbers may help to verify this property. Since 34/32=?3423^4 / 3^2 \stackrel{?}{=} 3^{4-2}, checking: 81/9=?3281/9 \stackrel{?}{=} 3^2, and indeed 9=99 = 9. Since 52/53=?1/5325^2 / 5^3 \stackrel{?}{=} 1/5^{3-2}, checking: 25/125=?1/525/125 \stackrel{?}{=} 1/5, and indeed 15=15\tfrac{1}{5} = \tfrac{1}{5}. When we work with numbers and the exponent is less than or equal to 33, we will apply the exponent. When the exponent is greater than 33, we leave the answer in exponential form.

Example. Simplify: (a) x10x8\tfrac{x^{10}}{x^8} (b) 2922\tfrac{2^9}{2^2}.

To simplify an expression with a quotient, we first compare the exponents in the numerator and denominator.

(a) Since 10>810 > 8, there are more factors of xx in the numerator, so we use the quotient property with m>nm > n: x10x8=x108=x2\tfrac{x^{10}}{x^8} = x^{10-8} = x^2.

(b) Since 9>29 > 2, there are more factors of 22 in the numerator, so we use the quotient property with m>nm > n: 2922=292=27\tfrac{2^9}{2^2} = 2^{9-2} = 2^7. Notice that when the larger exponent is in the numerator, we are left with factors in the numerator.

Simplify: x12x9\tfrac{x^{12}}{x^9}

Simplify: 71475\tfrac{7^{14}}{7^5}

Example. Simplify: (a) b10b15\tfrac{b^{10}}{b^{15}} (b) 3335\tfrac{3^3}{3^5}.

(a) Since 15>1015 > 10, there are more factors of bb in the denominator, so we use the quotient property with n>mn > m: b10b15=1b1510=1b5\tfrac{b^{10}}{b^{15}} = \tfrac{1}{b^{15-10}} = \tfrac{1}{b^5}.

(b) Since 5>35 > 3, there are more factors of 33 in the denominator: 3335=1353=132=19\tfrac{3^3}{3^5} = \tfrac{1}{3^{5-3}} = \tfrac{1}{3^2} = \tfrac{1}{9}. Notice that when the larger exponent is in the denominator, we are left with factors in the denominator and 11 in the numerator.

Simplify: x8x15\tfrac{x^8}{x^{15}}

Simplify: 12111221\tfrac{12^{11}}{12^{21}}

Example. Simplify: (a) a5a9\tfrac{a^5}{a^9} (b) x11x7\tfrac{x^{11}}{x^7}.

(a) Since 9>59 > 5, there are more aa’s in the denominator, so we end up with factors in the denominator: a5a9=1a95=1a4\tfrac{a^5}{a^9} = \tfrac{1}{a^{9-5}} = \tfrac{1}{a^4}.

(b) Since 11>711 > 7, there are more factors of xx in the numerator: x11x7=x117=x4\tfrac{x^{11}}{x^7} = x^{11-7} = x^4.

Simplify: b19b11\tfrac{b^{19}}{b^{11}}

Simplify: m9m17\tfrac{m^9}{m^{17}}

Simplify expressions with zero exponents

A special case of the Quotient Property is when the exponents of the numerator and denominator are equal, such as an expression like amam\tfrac{a^m}{a^m}. From earlier work with fractions, we know that 22=1\tfrac{2}{2} = 1, 1717=1\tfrac{17}{17} = 1, and 4343=1\tfrac{-43}{-43} = 1. In words, a number divided by itself is 11. So xx=1\tfrac{x}{x} = 1, for any xx (x0x \neq 0), since any number divided by itself is 11.

The Quotient Property of Exponents shows us how to simplify aman\tfrac{a^m}{a^n} when m>nm > n and when n<mn < m. What if m=nm = n?

Now we will simplify amam\tfrac{a^m}{a^m} in two ways to lead us to the definition of the zero exponent. Consider first 88\tfrac{8}{8}, which we know is 11. Writing 88 as 232^3: 2323=1\tfrac{2^3}{2^3} = 1. Subtracting exponents: 233=12^{3-3} = 1. Simplifying: 20=12^0 = 1.

In general, for a0a \neq 0, the pattern amam=amm=a0\tfrac{a^m}{a^m} = a^{m-m} = a^0 counts mm matching factors of aa in the numerator against mm matching factors of aa in the denominator, which cancel completely to 11. We see amam\tfrac{a^m}{a^m} simplifies to both a0a^0 and to 11. So a0=1a^0 = 1.

Zero Exponent. If aa is a non-zero number, then a0=1a^0 = 1. Any nonzero number raised to the zero power is 11.

In this text, we assume any variable that we raise to the zero power is not zero.

Example. Simplify: (a) 12012^0 (b) y0y^0.

The definition says any non-zero number raised to the zero power is 11. So 120=112^0 = 1 and y0=1y^0 = 1.

Simplify: 17017^0

Simplify: k0k^0

Now that we have defined the zero exponent, we can expand all the Properties of Exponents to include whole number exponents.

What about raising an expression to the zero power? Let’s look at (2x)0(2x)^0. We can use the Product to a Power Rule to rewrite this expression: using the rule, (2x)0=20x0(2x)^0 = 2^0 x^0; using the Zero Exponent Property, 20x0=112^0 x^0 = 1 \cdot 1; simplifying, this is 11. This tells us that any non-zero expression raised to the zero power is one.

Example. Simplify: (7z)0(7z)^0.

Using the definition of the zero exponent, (7z)0=1(7z)^0 = 1.

Simplify: (4y)0(-4y)^0

Simplify: (23x)0\left(\tfrac{2}{3} \cdot x\right)^0

Example. Simplify: (a) (3x2y)0(-3x^2y)^0 (b) 3x2y0-3x^2y^0.

(a) Here the entire product is raised to the zero power, so (3x2y)0=1(-3x^2y)^0 = 1.

(b) Here, notice that only the variable yy is being raised to the zero power — the exponent applies only to yy, not to the whole expression. Using the definition of the zero exponent on just that factor: 3x2y0=3x21=3x2-3x^2 y^0 = -3x^2 \cdot 1 = -3x^2.

Simplify: (7x2y)0(7x^2 y)^0

Simplify: 7x2y07x^2 y^0

Simplify expressions using the Quotient to a Power Property

Now we will look at an example that will lead us to the Quotient to a Power Property. Consider (xy)3\left(\tfrac{x}{y}\right)^3. This means xyxyxy\tfrac{x}{y} \cdot \tfrac{x}{y} \cdot \tfrac{x}{y}. Multiplying the fractions gives xxxyyy\tfrac{x \cdot x \cdot x}{y \cdot y \cdot y}, which written with exponents is x3y3\tfrac{x^3}{y^3}.

Notice that the exponent applies to both the numerator and the denominator. We see that (xy)3\left(\tfrac{x}{y}\right)^3 is x3y3\tfrac{x^3}{y^3}. This leads to the Quotient to a Power Property for Exponents.

Quotient to a Power Property of Exponents. If aa and bb are real numbers, b0b \neq 0, and mm is a counting number, then

(ab)m=ambm\left(\frac{a}{b}\right)^m = \frac{a^m}{b^m}

To raise a fraction to a power, raise the numerator and denominator to that power.

An example with numbers may help you understand this property: (23)3=?2333\left(\tfrac{2}{3}\right)^3 \stackrel{?}{=} \tfrac{2^3}{3^3}. Checking directly, 232323=?827\tfrac{2}{3} \cdot \tfrac{2}{3} \cdot \tfrac{2}{3} \stackrel{?}{=} \tfrac{8}{27}, and indeed 827=827\tfrac{8}{27} = \tfrac{8}{27}.

Example. Simplify: (a) (58)2\left(\tfrac{5}{8}\right)^2 (b) (x3)4\left(\tfrac{x}{3}\right)^4 (c) (ym)3\left(\tfrac{y}{m}\right)^3.

(a) Using the Quotient to a Power Property, (58)2=5282=2564\left(\tfrac{5}{8}\right)^2 = \tfrac{5^2}{8^2} = \tfrac{25}{64}.

(b) Using the Quotient to a Power Property, (x3)4=x434=x481\left(\tfrac{x}{3}\right)^4 = \tfrac{x^4}{3^4} = \tfrac{x^4}{81}.

(c) Raising the numerator and denominator to the third power, (ym)3=y3m3\left(\tfrac{y}{m}\right)^3 = \tfrac{y^3}{m^3}.

Simplify: (7/9)2(7/9)^2

Simplify: (y/8)3(y/8)^3

Simplify: (p/q)6(p/q)^6

Simplify expressions by applying several properties

We’ll now summarize all the properties of exponents so they are all together to refer to as we simplify expressions using several properties. Notice that they are now defined for whole number exponents.

Summary of exponent properties. If a,ba, b are real numbers and m,nm, n are whole numbers, then

Product Propertyaman=am+nPower Property(am)n=amnProduct to a Power Property(ab)m=ambmQuotient Propertyaman=amn, a0, m>naman=1anm, a0, n>mZero Exponent Definitiona0=1, a0Quotient to a Power Property(ab)m=ambm, b0 \begin{array}{ll} \text{Product Property} & a^m \cdot a^n = a^{m+n} \\[4pt] \text{Power Property} & (a^m)^n = a^{m \cdot n} \\[4pt] \text{Product to a Power Property} & (ab)^m = a^m b^m \\[4pt] \text{Quotient Property} & \tfrac{a^m}{a^n} = a^{m-n},\ a \neq 0,\ m > n \qquad \tfrac{a^m}{a^n} = \tfrac{1}{a^{n-m}},\ a \neq 0,\ n > m \\[8pt] \text{Zero Exponent Definition} & a^0 = 1,\ a \neq 0 \\[4pt] \text{Quotient to a Power Property} & \left(\tfrac{a}{b}\right)^m = \tfrac{a^m}{b^m},\ b \neq 0 \end{array}

Example. Simplify: (x2)3x5\tfrac{(x^2)^3}{x^5}.

Multiplying the exponents in the numerator using the Power Property gives x6x5\tfrac{x^6}{x^5}. Subtracting the exponents gives xx.

Simplify: (a4)5a9\tfrac{(a^4)^5}{a^9}

Simplify: (b5)6b11\tfrac{(b^5)^6}{b^{11}}

Example. Simplify: m8(m2)4\tfrac{m^8}{(m^2)^4}.

Multiplying the exponents in the denominator using the Power Property gives m8m8\tfrac{m^8}{m^8}. Subtracting the exponents gives m0m^0. Using the zero power property gives 11.

Simplify: k11(k3)3\tfrac{k^{11}}{(k^3)^3}

Simplify: d23(d4)6\tfrac{d^{23}}{(d^4)^6}

Example. Simplify: (x7x3)2\left(\tfrac{x^7}{x^3}\right)^2.

Remember parentheses come before exponents, and the bases are the same so we can simplify inside the parentheses first — subtracting the exponents gives (x73)2(x^{7-3})^2. Simplifying gives (x4)2(x^4)^2. Multiplying the exponents gives x8x^8.

Simplify: (r14r8)2\left(\tfrac{r^{14}}{r^8}\right)^2

Simplify: (b6b11)2\left(\tfrac{b^6}{b^{11}}\right)^2

Example. Simplify: (p2q5)3\left(\tfrac{p^2}{q^5}\right)^3.

Here we cannot simplify inside the parentheses first, since the bases are not the same. Instead we raise the numerator and denominator to the third power using the Quotient to a Power Property, giving (p2)3(q5)3\tfrac{(p^2)^3}{(q^5)^3}. Using the Power Property gives p6q15\tfrac{p^6}{q^{15}}.

Simplify: (m3n8)5\left(\tfrac{m^3}{n^8}\right)^5

Simplify: (t10u7)2\left(\tfrac{t^{10}}{u^7}\right)^2

Example. Simplify: (2x33y)4\left(\tfrac{2x^3}{3y}\right)^4.

Raising the numerator and denominator to the fourth power using the Quotient to a Power Property gives (2x3)4(3y)4\tfrac{(2x^3)^4}{(3y)^4}. Raising each factor to the fourth power using the Product to a Power Property gives 24(x3)434y4\tfrac{2^4 (x^3)^4}{3^4 y^4}. Using the Power Property and simplifying gives 16x1281y4\tfrac{16x^{12}}{81y^4}.

Simplify: (5b9c3)2\left(\tfrac{5b}{9c^3}\right)^2

Simplify: (4p47q5)3\left(\tfrac{4p^4}{7q^5}\right)^3

Example. Simplify: (y2)3(y2)4(y5)4\tfrac{(y^2)^3 (y^2)^4}{(y^5)^4}.

Using the Power Property throughout gives (y6)(y8)y20\tfrac{(y^6)(y^8)}{y^{20}}. Adding the exponents in the numerator using the Product Property gives y14y20\tfrac{y^{14}}{y^{20}}. Using the Quotient Property gives 1y6\tfrac{1}{y^6}.

Simplify: (y4)4(y3)5(y7)6\tfrac{(y^4)^4 \cdot (y^3)^5}{(y^7)^6}

Simplify: (3x4)2(x3)4(x5)3\tfrac{(3x^4)^2 \cdot (x^3)^4}{(x^5)^3}

Divide monomials

We have now seen all the properties of exponents. We’ll use them to divide monomials. Later, you’ll use them to divide polynomials.

Example. Find the quotient: 56x5÷7x256x^5 \div 7x^2.

Rewriting as a fraction gives 56x57x2\tfrac{56x^5}{7x^2}. Using fraction multiplication to separate the number part from the variable part gives 567x5x2\tfrac{56}{7} \cdot \tfrac{x^5}{x^2}. Using the Quotient Property gives 8x38x^3.

Find the quotient: 63x89x4\tfrac{63x^8}{9x^4}

Find the quotient: 96y116y8\tfrac{96y^{11}}{6y^8}

Example. Find the quotient: 42x2y37xy5\tfrac{42x^2y^3}{-7xy^5}.

Using fraction multiplication gives 427x2xy3y5\tfrac{42}{-7} \cdot \tfrac{x^2}{x} \cdot \tfrac{y^3}{y^5}. Simplifying and using the Quotient Property gives 6x1y2-6 \cdot x \cdot \tfrac{1}{y^2}. Multiplying gives 6xy2-\tfrac{6x}{y^2}.

Find the quotient: 84x8y37x10y2\tfrac{-84x^8 y^3}{7x^{10} y^2}

Find the quotient: 72a4b58a9b5\tfrac{-72a^4 b^5}{-8a^9 b^5}

Example. Find the quotient: 24a5b348ab4\tfrac{24a^5b^3}{48ab^4}.

Using fraction multiplication gives 2448a5ab3b4\tfrac{24}{48} \cdot \tfrac{a^5}{a} \cdot \tfrac{b^3}{b^4}. Simplifying and using the Quotient Property gives 12a41b\tfrac{1}{2} \cdot a^4 \cdot \tfrac{1}{b}. Multiplying gives a42b\tfrac{a^4}{2b}.

Find the quotient: 16a7b624ab8\tfrac{16a^7 b^6}{24ab^8}

Find the quotient: 27p4q745p12q\tfrac{27p^4 q^7}{-45p^{12} q}

Once you become familiar with the process and have practiced it step by step several times, you may be able to simplify a fraction in one step.

Example. Find the quotient: 14x7y1221x11y6\tfrac{14x^7y^{12}}{21x^{11}y^6}.

Simplifying directly and using the Quotient Property gives 2y63x4\tfrac{2y^6}{3x^4}. Be very careful to simplify 1421\tfrac{14}{21} by dividing out a common factor, and to simplify the variables by subtracting their exponents.

Find the quotient: 28x5y1449x9y12\tfrac{28x^5 y^{14}}{49x^9 y^{12}}

Find the quotient: 30m5n1148m10n14\tfrac{30m^5 n^{11}}{48m^{10} n^{14}}

In all examples so far, there was no work to do in the numerator or denominator before simplifying the fraction. In the next example, we’ll first find the product of two monomials in the numerator before we simplify the fraction.

Example. Find the quotient: (3x3y2)(10x2y3)6x4y5\tfrac{(3x^3y^2)(10x^2y^3)}{6x^4y^5}.

Remember, the fraction bar is a grouping symbol. We will simplify the numerator first. Simplifying the numerator gives 30x5y56x4y5\tfrac{30x^5y^5}{6x^4y^5}. Simplifying, using the Quotient Rule, gives 5x5x.

Find the quotient: (3x4y5)(8x2y5)12x5y8\tfrac{(3x^4 y^5)(8x^2 y^5)}{12x^5 y^8}

Find the quotient: (6a6b9)(8a5b8)12a10b12\tfrac{(-6a^6 b^9)(-8a^5 b^8)}{-12a^{10} b^{12}}

Key terms

Quotient Property of Exponents — for a real number a0a \neq 0 and whole numbers m,nm, n: aman=amn\tfrac{a^m}{a^n} = a^{m-n} when m>nm > n, and aman=1anm\tfrac{a^m}{a^n} = \tfrac{1}{a^{n-m}} when n>mn > m. zero exponent — any nonzero number or expression raised to the power 00 equals 11. Quotient to a Power Property(ab)m=ambm\left(\tfrac{a}{b}\right)^m = \tfrac{a^m}{b^m} for b0b \neq 0. monomial — a single term made of a coefficient and variables raised to whole-number powers, divided using these exponent properties one variable at a time.


This section is adapted from Prealgebra 2e, Section 10.4: Divide Monomials by Lynn Marecek, MaryAnne Anthony-Smith, and Andrea Honeycutt Mathis, © OpenStax, licensed under CC BY-NC-SA 4.0. Access the original for free at openstax.org. Changes: omitted the Be Prepared quiz, Self Check checklist, Media links, and end-of-section exercises; and converted the practice problems (“Try Its”) into interactive exercises with instant feedback.