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Functions and Function Notation

Functions and Function Notation

By the end of this section, you will be able to: determine whether a relation represents a function, find the value of a function, determine whether a function is one-to-one, use the vertical line test to identify functions, and graph the functions listed in the library of functions.

A jetliner changes altitude as its distance from the starting point of a flight increases. The weight of a growing child increases with time. In each case, one quantity depends on another. There is a relationship between the two quantities that we can describe, analyze, and use to make predictions. In this section, we will analyze such relationships.

Determining whether a relation represents a function

A relation is a set of ordered pairs. The set of the first components of each ordered pair is called the domain and the set of the second components of each ordered pair is called the range. Consider the following set of ordered pairs. The first numbers in each pair are the first five natural numbers. The second number in each pair is twice that of the first.

{(1,2),(2,4),(3,6),(4,8),(5,10)}\{(1,2),(2,4),(3,6),(4,8),(5,10)\}

The domain is {1,2,3,4,5}\{1,2,3,4,5\}. The range is {2,4,6,8,10}\{2,4,6,8,10\}.

Note that each value in the domain is also known as an input value, or independent variable, and is often labeled with the lowercase letter xx. Each value in the range is also known as an output value, or dependent variable, and is often labeled lowercase letter yy.

A function ff is a relation that assigns a single value in the range to each value in the domain. In other words, no xx-values are repeated. For our example that relates the first five natural numbers to numbers double their values, this relation is a function because each element in the domain, {1,2,3,4,5}\{1,2,3,4,5\}, is paired with exactly one element in the range, {2,4,6,8,10}\{2,4,6,8,10\}.

Now let’s consider the set of ordered pairs that relates the terms “even” and “odd” to the first five natural numbers. It would appear as

{(odd,1),(even,2),(odd,3),(even,4),(odd,5)}\{(\text{odd},1),(\text{even},2),(\text{odd},3),(\text{even},4),(\text{odd},5)\}

Notice that each element in the domain, {even,odd}\{\text{even},\text{odd}\} is not paired with exactly one element in the range, {1,2,3,4,5}\{1,2,3,4,5\}. For example, the term “odd” corresponds to three values from the range, {1,3,5}\{1,3,5\}, and the term “even” corresponds to two values from the range, {2,4}\{2,4\}. This violates the definition of a function, so this relation is not a function.

The three diagrams below compare relations that are functions and not functions.

InputsOutputspqrmn(a)
InputsOutputspqrxyz(b)
InputsOutputspqxyz(c)

Diagram (a) is a function because each input is associated with a single output. Note that inputs qq and rr both give output nn. Diagram (b) is also a function. In this case, each input is associated with a single output. Diagram (c) is not a function because input qq is associated with two different outputs.

Function. A function is a relation in which each possible input value leads to exactly one output value. We say “the output is a function of the input.”

The input values make up the domain, and the output values make up the range.

How to: given a relationship between two quantities, determine whether the relationship is a function.

  1. Identify the input values.
  2. Identify the output values.
  3. If each input value leads to only one output value, classify the relationship as a function. If any input value leads to two or more outputs, do not classify the relationship as a function.

Example. The coffee shop menu below consists of items and their prices.

ItemPrice
Plain Donut1.49
Jelly Donut1.99
Chocolate Donut1.99

(a) Is price a function of the item?

(b) Is the item a function of the price?

Solution. (a) Let’s begin by considering the input as the items on the menu. The output values are then the prices.

MenuItemPricePlain DonutJelly DonutChocolate Donut1.491.991.99

Each item on the menu has only one price, so the price is a function of the item.

(b) Two items on the menu have the same price. If we consider the prices to be the input values and the items to be the output, then the same input value could have more than one output associated with it.

MenuItemPricePlain DonutJelly DonutChocolate Donut1.491.991.99

Therefore, the item is not a function of price.

Example. In a particular math class, the overall percent grade corresponds to a grade point average. Is grade point average a function of the percent grade? Is the percent grade a function of the grade point average? The table below shows a possible rule for assigning grade points.

Percent grade0–5657–6162–6667–7172–7778–8687–9192–100
Grade point average0.01.01.52.02.53.03.54.0

Solution. For any percent grade earned, there is an associated grade point average, so the grade point average is a function of the percent grade. In other words, if we input the percent grade, the output is a specific grade point average.

In the grading system given, there is a range of percent grades that correspond to the same grade point average. For example, students who receive a grade point average of 3.0 could have a variety of percent grades ranging from 78 all the way to 86. Thus, percent grade is not a function of grade point average.

The table below lists the five greatest baseball players of all time in order of rank.

PlayerRank
Babe Ruth1
Willie Mays2
Ty Cobb3
Walter Johnson4
Hank Aaron5

Using the table of baseball players above, is the rank a function of the player name?

Using the same table, is the player name a function of the rank?

Using function notation

Once we determine that a relationship is a function, we need to display and define the functional relationships so that we can understand and use them, and sometimes also so that we can program them into computers. There are various ways of representing functions. A standard function notation is one representation that facilitates working with functions.

To represent “height is a function of age,” we start by identifying the descriptive variables hh for height and aa for age. The letters ff, gg, and hh are often used to represent functions just as we use xx, yy, and zz to represent numbers and AA, BB, and CC to represent sets.

h is f of aWe name the function f; height is a function of age.h=f(a)We use parentheses to indicate the function input.f(a)We name the function f; the expression is read as “f of a.” \begin{array}{ll} h\text{ is }f\text{ of }a & \text{We name the function }f;\text{ height is a function of age.} \\[4pt] h=f(a) & \text{We use parentheses to indicate the function input.} \\[4pt] f(a) & \text{We name the function }f;\text{ the expression is read as ``}f\text{ of }a\text{.''} \end{array}

Remember, we can use any letter to name the function; the notation h(a)h(a) shows us that hh depends on aa. The value aa must be put into the function hh to get a result. The parentheses indicate that age is input into the function; they do not indicate multiplication.

We can also give an algebraic expression as the input to a function. For example f(a+b)f(a+b) means “first add aa and bb, and the result is the input for the function ff.” The operations must be performed in this order to obtain the correct result.

Function notation. The notation y=f(x)y=f(x) defines a function named ff. This is read as “yy is a function of xx.” The letter xx represents the input value, or independent variable. The letter yy, or f(x)f(x), represents the output value, or dependent variable.

Example. Use function notation to represent a function whose input is the name of a month and output is the number of days in that month. Assume that the domain does not include leap years.

Solution. The number of days in a month is a function of the name of the month, so if we name the function ff, we write days=f(month)\text{days}=f(\text{month}) or d=f(m)d=f(m). The name of the month is the input to a “rule” that associates a specific number (the output) with each input.

31=f(January)outputruleinput

For example, f(March)=31f(\text{March})=31, because March has 31 days. The notation d=f(m)d=f(m) reminds us that the number of days, dd (the output), is dependent on the name of the month, mm (the input).

Analysis. Note that the inputs to a function do not have to be numbers; function inputs can be names of people, labels of geometric objects, or any other element that determines some kind of output. However, most of the functions we will work with in this book will have numbers as inputs and outputs.

Example. A function N=f(y)N=f(y) gives the number of police officers, NN, in a town in year yy. What does f(2005)=300f(2005)=300 represent?

Solution. When we read f(2005)=300f(2005)=300, we see that the input year is 2005. The value for the output, the number of police officers (N)(N), is 300. Remember, N=f(y)N=f(y). The statement f(2005)=300f(2005)=300 tells us that in the year 2005 there were 300 police officers in the town.

Use function notation to express the weight of a pig in pounds as a function of its age in days dd. Which statement says this?

Q&A. Instead of a notation such as y=f(x)y=f(x), could we use the same symbol for the output as for the function, such as y=y(x)y=y(x), meaning “yy is a function of xx?”

Yes, this is often done, especially in applied subjects that use higher math, such as physics and engineering. However, in exploring math itself we like to maintain a distinction between a function such as ff, which is a rule or procedure, and the output yy we get by applying ff to a particular input xx. This is why we usually use notation such as y=f(x)y=f(x), P=W(d)P=W(d), and so on.

Representing functions using tables

A common method of representing functions is in the form of a table. The table rows or columns display the corresponding input and output values. In some cases, these values represent all we know about the relationship; other times, the table provides a few select examples from a more complete relationship.

The table below lists the input number of each month (January = 1, February = 2, and so on) and the output value of the number of days in that month. This information represents all we know about the months and days for a given year (that is not a leap year). Note that, in this table, we define a days-in-a-month function ff where D=f(m)D=f(m) identifies months by an integer rather than by name.

Month number, mm (input)123456789101112
Days in month, DD (output)312831303130313130313031

The next table defines a function Q=g(n)Q=g(n). Remember, this notation tells us that gg is the name of the function that takes the input nn and gives the output QQ.

nn12345
QQ86768

The third table displays the age of children in years and their corresponding heights. This table displays just some of the data available for the heights and ages of children. We can see right away that this table does not represent a function because the same input value, 5 years, has two different output values, 40 in. and 42 in.

Age in years, aa (input)55678910
Height in inches, hh (output)40424447505254

How to: given a table of input and output values, determine whether the table represents a function.

  1. Identify the input and output values.
  2. Check to see if each input value is paired with only one output value. If so, the table represents a function.

Example. Which table, A, B, or C, represents a function (if any)?

Table A:

InputOutput
21
53
86

Table B:

InputOutput
−35
01
45

Table C:

InputOutput
10
52
54

Solution. Tables A and B define functions. In both, each input value corresponds to exactly one output value. Table C does not define a function because the input value of 5 corresponds to two different output values.

When a table represents a function, corresponding input and output values can also be specified using function notation. The function represented by table A can be represented by writing

f(2)=1,f(5)=3,andf(8)=6f(2)=1,\quad f(5)=3,\quad \text{and}\quad f(8)=6

Similarly, the statements

g(3)=5,g(0)=1,andg(4)=5g(-3)=5,\quad g(0)=1,\quad \text{and}\quad g(4)=5

represent the function in table B. Table C cannot be expressed in a similar way because it does not represent a function.

Does the table with inputs 1,2,31,2,3 and matching outputs 10,100,100010,100,1000 represent a function?

Finding input and output values of a function

When we know an input value and want to determine the corresponding output value for a function, we evaluate the function. Evaluating will always produce one result because each input value of a function corresponds to exactly one output value.

When we know an output value and want to determine the input values that would produce that output value, we set the output equal to the function’s formula and solve for the input. Solving can produce more than one solution because different input values can produce the same output value.

Evaluation of functions in algebraic forms

When we have a function in formula form, it is usually a simple matter to evaluate the function. For example, the function f(x)=53x2f(x)=5-3x^2 can be evaluated by squaring the input value, multiplying by 3, and then subtracting the product from 5.

How to: given the formula for a function, evaluate.

  1. Substitute the input variable in the formula with the value provided.
  2. Calculate the result.

Example. Evaluate f(x)=x2+3x4f(x)=x^2+3x-4 at:

(a) 22   (b) aa   (c) a+ha+h   (d) Now evaluate f(a+h)f(a)h\tfrac{f(a+h)-f(a)}{h}

Solution. Replace the xx in the function with each specified value.

(a) Because the input value is a number, 2, we can use simple algebra to simplify.

f(2)=22+3(2)4=4+64=6 \begin{array}{lrcl} & f(2) &=& 2^2+3(2)-4 \\[4pt] & &=& 4+6-4 \\[4pt] & &=& 6 \end{array}

(b) In this case, the input value is a letter so we cannot simplify the answer any further.

f(a)=a2+3a4f(a)=a^2+3a-4

(c) With an input value of a+ha+h, we must use the distributive property.

f(a+h)=(a+h)2+3(a+h)4=a2+2ah+h2+3a+3h4 \begin{array}{lrcl} & f(a+h) &=& (a+h)^2+3(a+h)-4 \\[4pt] & &=& a^2+2ah+h^2+3a+3h-4 \end{array}

(d) In this case, we apply the input values to the function more than once, and then perform algebraic operations on the result. We already found that

f(a+h)=a2+2ah+h2+3a+3h4f(a+h)=a^2+2ah+h^2+3a+3h-4

and we know that

f(a)=a2+3a4f(a)=a^2+3a-4

Now we combine the results and simplify.

f(a+h)f(a)h=(a2+2ah+h2+3a+3h4)(a2+3a4)h=2ah+h2+3hhFactor out h.=h(2a+h+3)hSimplify.=2a+h+3 \begin{array}{lrcl} & \tfrac{f(a+h)-f(a)}{h} &=& \tfrac{(a^2+2ah+h^2+3a+3h-4)-(a^2+3a-4)}{h} \\[4pt] & &=& \tfrac{2ah+h^2+3h}{h} \\[4pt] \text{Factor out }h. & &=& \tfrac{h(2a+h+3)}{h} \\[4pt] \text{Simplify.} & &=& 2a+h+3 \end{array}

Example. Given the function h(p)=p2+2ph(p)=p^2+2p, evaluate h(4)h(4).

Solution. To evaluate h(4)h(4), we substitute the value 4 for the input variable pp in the given function.

h(p)=p2+2ph(4)=(4)2+2(4)=16+8=24 \begin{array}{lrcl} & h(p) &=& p^2+2p \\[4pt] & h(4) &=& (4)^2+2(4) \\[4pt] & &=& 16+8 \\[4pt] & &=& 24 \end{array}

Therefore, for an input of 4, we have an output of 24.

Given the function g(m)=m4g(m)=\sqrt{m-4}, evaluate g(5)g(5).

Example. Given the function h(p)=p2+2ph(p)=p^2+2p, solve for h(p)=3h(p)=3.

Solution.

h(p)=3Substitute the original function h(p)=p2+2p.p2+2p=3Subtract 3 from each side.p2+2p3=0Factor.(p+3)(p1)=0 \begin{array}{lrcl} & h(p) &=& 3 \\[4pt] \text{Substitute the original function }h(p)=p^2+2p. & p^2+2p &=& 3 \\[4pt] \text{Subtract 3 from each side.} & p^2+2p-3 &=& 0 \\[4pt] \text{Factor.} & (p+3)(p-1) &=& 0 \end{array}

If (p+3)(p1)=0(p+3)(p-1)=0, either (p+3)=0(p+3)=0 or (p1)=0(p-1)=0 (or both of them equal 0). We will set each factor equal to 0 and solve for pp in each case.

(p+3)=0,p=3(p1)=0,p=1 \begin{array}{lrcl} & (p+3) &=& 0,\quad p=-3 \\[4pt] & (p-1) &=& 0,\quad p=1 \end{array}

This gives us two solutions. The output h(p)=3h(p)=3 when the input is either p=1p=1 or p=3p=-3. We can also verify by graphing. The graph verifies that h(1)=h(3)=3h(1)=h(-3)=3 and h(4)=24h(4)=24.

ph(p)−5−4−3−2−112345−55101520253035
pp−3−2014
h(p)h(p)300324

Given the function g(m)=m4g(m)=\sqrt{m-4}, solve g(m)=2g(m)=2.

Evaluating functions expressed in formulas

Some functions are defined by mathematical rules or procedures expressed in equation form. If it is possible to express the function output with a formula involving the input quantity, then we can define a function in algebraic form. For example, the equation 2n+6p=122n+6p=12 expresses a functional relationship between nn and pp. We can rewrite it to decide if pp is a function of nn.

How to: given a function in equation form, write its algebraic formula.

  1. Solve the equation to isolate the output variable on one side of the equal sign, with the other side as an expression that involves only the input variable.
  2. Use all the usual algebraic methods for solving equations, such as adding or subtracting the same quantity to or from both sides, or multiplying or dividing both sides of the equation by the same quantity.

Example. Express the relationship 2n+6p=122n+6p=12 as a function p=f(n)p=f(n), if possible.

Solution. To express the relationship in this form, we need to be able to write the relationship where pp is a function of nn, which means writing it as p=[expression involving n]p=[\text{expression involving }n].

2n+6p=12Subtract 2n from both sides.6p=122nDivide both sides by 6 and simplify.p=122n6p=1262n6p=213n \begin{array}{lrcl} & 2n+6p &=& 12 \\[4pt] \text{Subtract }2n\text{ from both sides.} & 6p &=& 12-2n \\[4pt] \text{Divide both sides by 6 and simplify.} & p &=& \tfrac{12-2n}{6} \\[4pt] & p &=& \tfrac{12}{6}-\tfrac{2n}{6} \\[4pt] & p &=& 2-\tfrac{1}{3}n \end{array}

Therefore, pp as a function of nn is written as

p=f(n)=213np=f(n)=2-\tfrac{1}{3}n

Analysis. It is important to note that not every relationship expressed by an equation can also be expressed as a function with a formula.

Example. Does the equation x2+y2=1x^2+y^2=1 represent a function with xx as input and yy as output? If so, express the relationship as a function y=f(x)y=f(x).

Solution. First we subtract x2x^2 from both sides.

y2=1x2y^2=1-x^2

We now try to solve for yy in this equation.

y=±1x2=+1x2 and 1x2 \begin{array}{lrcl} & y &=& \pm\sqrt{1-x^2} \\[4pt] & &=& +\sqrt{1-x^2}\ \text{and}\ -\sqrt{1-x^2} \end{array}

We get two outputs corresponding to the same input, so this relationship cannot be represented as a single function y=f(x)y=f(x).

If x8y3=0x-8y^3=0, express yy as a function of xx.

Q&A. Are there relationships expressed by an equation that do represent a function but which still cannot be represented by an algebraic formula?

Yes, this can happen. For example, given the equation x=y+2yx=y+2^y, if we want to express yy as a function of xx, there is no simple algebraic formula involving only xx that equals yy. However, each xx does determine a unique value for yy, and there are mathematical procedures by which yy can be found to any desired accuracy. In this case, we say that the equation gives an implicit (implied) rule for yy as a function of xx, even though the formula cannot be written explicitly.

Evaluating a function given in tabular form

As we saw above, we can represent functions in tables. Conversely, we can use information in tables to write functions, and we can evaluate functions using the tables. For example, how well do our pets recall the fond memories we share with them? There is an urban legend that a goldfish has a memory of 3 seconds, but this is just a myth. Goldfish can remember up to 3 months, while the beta fish has a memory of up to 5 months. And while a puppy’s memory span is no longer than 30 seconds, the adult dog can remember for 5 minutes. This is meager compared to a cat, whose memory span lasts for 16 hours.

The function that relates the type of pet to the duration of its memory span is more easily visualized with the use of a table.

PetMemory span in hours
Puppy0.008
Adult dog0.083
Cat16
Goldfish2160
Beta fish3600

At times, evaluating a function in table form may be more useful than using equations. Here let us call the function PP. The domain of the function is the type of pet and the range is a real number representing the number of hours the pet’s memory span lasts. We can evaluate the function PP at the input value of “goldfish.” We would write P(goldfish)=2160P(\text{goldfish})=2160. Notice that, to evaluate the function in table form, we identify the input value and the corresponding output value from the pertinent row of the table. The tabular form for function PP seems ideally suited to this function, more so than writing it in paragraph or function form.

How to: given a function represented by a table, identify specific output and input values.

  1. Find the given input in the row (or column) of input values.
  2. Identify the corresponding output value paired with that input value.
  3. Find the given output values in the row (or column) of output values, noting every time that output value appears.
  4. Identify the input value(s) corresponding to the given output value.

Example. Using the table below, (a) evaluate g(3)g(3), and (b) solve g(n)=6g(n)=6.

nn12345
g(n)g(n)86768

Solution. (a) Evaluating g(3)g(3) means determining the output value of the function gg for the input value of n=3n=3. The table output value corresponding to n=3n=3 is 7, so g(3)=7g(3)=7.

(b) Solving g(n)=6g(n)=6 means identifying the input values, nn, that produce an output value of 6. The table shows two solutions: 22 and 44. When we input 2 into the function gg, our output is 6. When we input 4 into the function gg, our output is also 6.

Using the table above, evaluate g(1)g(1).

Finding function values from a graph

Evaluating a function using a graph also requires finding the corresponding output value for a given input value, only in this case, we find the output value by looking at the graph. Solving a function equation using a graph requires finding all instances of the given output value on the graph and observing the corresponding input value(s).

Example. Given the graph below, (a) evaluate f(2)f(2), and (b) solve f(x)=4f(x)=4.

xf(x)−5−4−3−2−112345−3−2−11234567

Solution. (a) To evaluate f(2)f(2), locate the point on the curve where x=2x=2, then read the yy-coordinate of that point. The point has coordinates (2,1)(2,1), so f(2)=1f(2)=1.

xf(x)−5−4−3−2−112345−3−2−11234567(2, 1)

(b) To solve f(x)=4f(x)=4, we find the output value 44 on the vertical axis. Moving horizontally along the line y=4y=4, we locate two points of the curve with output value 44: (1,4)(-1,4) and (3,4)(3,4). These points represent the two solutions to f(x)=4f(x)=4: 1-1 or 33. This means f(1)=4f(-1)=4 and f(3)=4f(3)=4, or when the input is 1-1 or 33, the output is 44.

xf(x)−5−4−3−2−112345−3−2−11234567(−1, 4)(3, 4)

Using the graph above, solve f(x)=1f(x)=1. Enter both solutions, separated by a comma.

Determining whether a function is one-to-one

Some functions have a given output value that corresponds to two or more input values. For example, in the stock chart shown in the figure at the beginning of this chapter, the stock price was $1000 on five different dates, meaning that there were five different input values that all resulted in the same output value of $1000.

However, some functions have only one input value for each output value, as well as having only one output for each input. We call these functions one-to-one functions. As an example, consider a school that uses only letter grades and decimal equivalents, as listed below.

Letter gradeGrade point average
A4.0
B3.0
C2.0
D1.0

This grading system represents a one-to-one function, because each letter input yields one particular grade point average output and each grade point average corresponds to one input letter.

To visualize this concept, let’s look again at the two simple functions sketched in diagrams (a) and (b) at the start of this section. The function in diagram (a) shows a relationship that is not a one-to-one function because inputs qq and rr both give output nn. The function in diagram (b) shows a relationship that is a one-to-one function because each input is associated with a single output.

One-to-one function. A one-to-one function is a function in which each output value corresponds to exactly one input value.

Example. Is the area of a circle a function of its radius? If yes, is the function one-to-one?

Solution. A circle of radius rr has a unique area measure given by A=πr2A=\pi r^2, so for any input, rr, there is only one output, AA. The area is a function of radius rr.

If the function is one-to-one, the output value, the area, must correspond to a unique input value, the radius. Any area measure AA is given by the formula A=πr2A=\pi r^2. Because areas and radii are positive numbers, there is exactly one solution: Aπ\sqrt{\tfrac{A}{\pi}}. So the area of a circle is a one-to-one function of the circle’s radius.

Is a balance a function of the bank account number?

Is a bank account number a function of the balance?

If each percent grade earned in a course translates to one letter grade, is the letter grade a one-to-one function of the percent grade?

Using the vertical line test

As we have seen in some examples above, we can represent a function using a graph. Graphs display a great many input-output pairs in a small space. The visual information they provide often makes relationships easier to understand. By convention, graphs are typically constructed with the input values along the horizontal axis and the output values along the vertical axis.

The most common graphs name the input value xx and the output value yy, and we say yy is a function of xx, or y=f(x)y=f(x) when the function is named ff. The graph of the function is the set of all points (x,y)(x,y) in the plane that satisfies the equation y=f(x)y=f(x). If the function is defined for only a few input values, then the graph of the function is only a few points, where the xx-coordinate of each point is an input value and the yy-coordinate of each point is the corresponding output value. For example, the black dots on the graph below tell us that f(0)=2f(0)=2 and f(6)=1f(6)=1. However, the set of all points (x,y)(x,y) satisfying y=f(x)y=f(x) is a curve. The curve shown includes (0,2)(0,2) and (6,1)(6,1) because the curve passes through those points.

xy

The vertical line test can be used to determine whether a graph represents a function. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.

xy
xy
xy

The first graph is a function: every vertical line meets it exactly once. The second and third are not functions, because a vertical line meets each of them at two points.

How to: given a graph, use the vertical line test to determine if the graph represents a function.

  1. Inspect the graph to see if any vertical line drawn would intersect the curve more than once.
  2. If there is any such line, determine that the graph does not represent a function.

Example. Which of the graphs below represent(s) a function y=f(x)y=f(x)?

xf(x)−4−3−2−11234−5−4−3−2−112345
xy3456789101112
xf(x)−4−3−2−11234−5−4−3−2−112345

Solution. If any vertical line intersects a graph more than once, the relation represented by the graph is not a function. Notice that any vertical line would pass through only one point of the two graphs shown in parts (a) and (b). From this we can conclude that these two graphs represent functions. The third graph does not represent a function because, at most xx-values, a vertical line would intersect the graph at more than one point, as shown below.

xf(x)−5−4−3−2−112345−5−4−3−2−112345
xy−4−3−2−11234−4−3−2−11234

Does the graph of y=xy=\lvert x\rvert shown above represent a function?

Using the horizontal line test

Once we have determined that a graph defines a function, an easy way to determine if it is a one-to-one function is to use the horizontal line test. Draw horizontal lines through the graph. If any horizontal line intersects the graph more than once, then the graph does not represent a one-to-one function.

How to: given a graph of a function, use the horizontal line test to determine if the graph represents a one-to-one function.

  1. Inspect the graph to see if any horizontal line drawn would intersect the curve more than once.
  2. If there is any such line, determine that the function is not one-to-one.

Example. Consider the two functions graphed earlier in parts (a) and (b) of the vertical line test example. Are either of the functions one-to-one?

Solution. The function in part (a) is not one-to-one. The horizontal line shown below intersects the graph of the function at two points (and we can even find horizontal lines that intersect it at three points).

xf(x)−4−3−2−11234−5−4−3−2−112345

The function in part (b) is one-to-one. Any horizontal line will intersect a diagonal line at most once.

Is the circle graphed in part (c) of the vertical line test example one-to-one?

Identifying basic toolkit functions

In this text, we will be exploring functions—the shapes of their graphs, their unique characteristics, their algebraic formulas, and how to solve problems with them. When learning to read, we start with the alphabet. When learning to do arithmetic, we start with numbers. When working with functions, it is similarly helpful to have a base set of building-block elements. We call these our “toolkit functions,” which form a set of basic named functions for which we know the graph, formula, and special properties. Some of these functions are programmed to individual buttons on many calculators. For these definitions we will use xx as the input variable and y=f(x)y=f(x) as the output variable.

We will see these toolkit functions, combinations of toolkit functions, their graphs, and their transformations frequently throughout this book. It will be very helpful if we can recognize these toolkit functions and their features quickly by name, formula, graph, and basic table properties.

Constantf(x)=cf(x)=c, where cc is a constant

xy−4−224−4−224

Identityf(x)=xf(x)=x

xy−4−224−4−224

Absolute valuef(x)=xf(x)=\lvert x\rvert

xy−4−224−4−224

Quadraticf(x)=x2f(x)=x^2

xy−4−224−4−224

Cubicf(x)=x3f(x)=x^3

xy−4−224−4−224

Reciprocalf(x)=1xf(x)=\tfrac{1}{x}

xy−4−224−4−224

Reciprocal squaredf(x)=1x2f(x)=\tfrac{1}{x^2}

xy−4−224246

Square rootf(x)=xf(x)=\sqrt{x}

xy−4−224−4−224

Cube rootf(x)=x3f(x)=\sqrt[3]{x}

xy−4−224−4−224

Key equations

Constant functionf(x)=cf(x)=c, where cc is a constant
Identity functionf(x)=xf(x)=x
Absolute value functionf(x)=xf(x)=\lvert x\rvert
Quadratic functionf(x)=x2f(x)=x^2
Cubic functionf(x)=x3f(x)=x^3
Reciprocal functionf(x)=1xf(x)=\tfrac{1}{x}
Reciprocal squared functionf(x)=1x2f(x)=\tfrac{1}{x^2}
Square root functionf(x)=xf(x)=\sqrt{x}
Cube root functionf(x)=x3f(x)=\sqrt[3]{x}

Key concepts

  • A relation is a set of ordered pairs. A function is a specific type of relation in which each domain value, or input, leads to exactly one range value, or output.
  • Function notation is a shorthand method for relating the input to the output in the form y=f(x)y=f(x).
  • In tabular form, a function can be represented by rows or columns that relate to input and output values.
  • To evaluate a function, we determine an output value for a corresponding input value. Algebraic forms of a function can be evaluated by replacing the input variable with a given value.
  • To solve for a specific function value, we determine the input values that yield the specific output value.
  • An algebraic form of a function can be written from an equation.
  • Input and output values of a function can be identified from a table.
  • Relating input values to output values on a graph is another way to evaluate a function.
  • A function is one-to-one if each output value corresponds to only one input value.
  • A graph represents a function if any vertical line drawn on the graph intersects the graph at no more than one point.
  • The graph of a one-to-one function passes the horizontal line test.

Key terms

relation — a set of ordered pairs. domain — the set of all input values of a relation. range — the set of all output values of a relation. independent variable — an input value of a function. dependent variable — an output value of a function. function — a relation in which each input value yields a unique output value. function notation — the notation y=f(x)y=f(x), defining a function named ff with input xx and output yy. one-to-one function — a function for which each value of the output is associated with a unique input value. vertical line test — a method of testing whether a graph represents a function by determining whether a vertical line intersects the graph no more than once. horizontal line test — a method of testing whether a function is one-to-one by determining whether any horizontal line intersects the graph more than once.


This section is adapted from Precalculus 2e, Section 1.1: Functions and Function Notation by Jay Abramson and OpenStax, © OpenStax, licensed under CC BY-NC-SA 4.0. Access the original for free at openstax.org. Changes: recreated every figure as an accessible inline SVG, including the input–output mapping diagrams, the coffee shop menu mappings, and the function-machine diagram; presented the menu itself and the toolkit function library as Markdown tables and headed figure groups rather than images; omitted the media links and end-of-section exercises; converted the practice problems (“Try Its”) into interactive exercises with instant feedback; and presented the write-a-function-notation practice item as multiple choice so it can be graded in the browser.